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3 years ago

△ABC ~ △DEF as shown in the diagram below:

Mathematics

2 answers:

Vitek1552 [10]3 years ago

7 0

AB ≈ ED ( corresponding sides )

∠A ≈ ∠D ( corresponding angles )

∠C ≈ ∠F ( corresponding angles )

Mademuasel [1]3 years ago

7 0

Answer:

Ab=ED

Step-by-step explanation:

The first one

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Find the indicated value<br> f(x)<br> -<br> {3(x+1)+1.851<br> find f(0)<br> >

Tpy6a [65]

Answer:

Step-by-step explanation:

6 0

2 years ago

An exponential random variable has a standard deviation of 16. Calculate The probability that it takes on a value < 11. Use 3

antiseptic1488 [7]

Answer:

$P(X$

And using the cdf we got:

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable that represent the random variable of interest and we know that the distribution is given by:

$X \sim Exp(\lambda)$

We know the variance on this case given by :

$Var(X) = \frac{1}{\lambda^2}$

So then the deviation is given by:

$Sd(X) = \frac{1}{\sqrt{\lambda}}$

And if we solve for $\lambda$ we got:

$\lambda = (\frac{1}{16})^2 = \frac{1}{256}$

The cumulative distribution function for the exponential distribution is given by:

$F(x) = 1- e^{-\lambda x}$

Solution to the problem

And for this case we want to find this probability:

$P(X$

And using the cdf we got:

$P(X$

5 0

2 years ago

What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta

katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

$\frac{x}{x^2-16}-\frac{3}{x-4}$

To solve the given expression

$\frac{x}{x^2-16}-\frac{3}{x-4}$

$=\frac{x}{x^2-4^2}-\frac{3}{x-4}$

$=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}$ ( using the property $a^2-b^2=(a+b)(a-b)$ )

$=\frac{x-3(x+4)}{(x+4)(x-4)}$

$=\frac{x-3x-12}{(x+4)(x-4)}$ ( by using distributive property )

$=\frac{-2x-12}{(x+4)(x-4)}$

$=\frac{-2(x+6)}{(x+4)(x-4)}$

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

5 0

3 years ago

Read 2 more answers

Can someone help me with this two problems?

ANEK [815]

2x+4y=0

substitute y with 0

2x+4(0)=0

solve the equation

2x+0=0

2x=0

divide by 2 on both sides

x=0

4x+8y=7

substitute y with 0

4x+8(0)=7

solve the equation

4x+0=7

4x=7

divide by 4 on both sides

x=7/4 or x=1 3/4 or x=1.75

3x-7y=-29

2x+2y=6

solve the bottom equation

3x-7y=-29

x=3-y

substitute for x

3(3-y)-7y=-29

solve the equation

y=19/5

now substitute for y

x=3- $\frac{19}{5}$

solve for x

x=-4/5

the possible solution of the system is the ordered pair

(x,y)=( $-\frac{4}{5} ,\frac{19}{5}$ )

3 0

3 years ago

What is the distance between points M and N?

Free_Kalibri [48]

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

<h3>How to determine the distance between two points</h3>

In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:

$\cos L = \frac{(19.6\,m)^{2}-(14.8\,m)^{2}-(21.4\,m)^{2}}{-2\cdot (14.8\,m)\cdot (21.4\,m)}$

L ≈ 62.464°

Then, we get the distance between points M and N by the law of the cosine once again:

$MN = \sqrt{(7.4\,m)^{2}+(10.7\,m)^{2}-2\cdot (7.4\,m)\cdot (10.7\,m)\cdot \cos 62.464^{\circ}}$

MN ≈ 9.8 m

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

To learn more on triangles: brainly.com/question/2773823

#SPJ1

6 0

1 year ago