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kati45 [8]
3 years ago
9

What is the value of arcsin(0) in degrees? Enter your answer in the box.

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

Therefore,

The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.

Step-by-step explanation:

To Find:

arcsin(0) in degrees =?

Solution:

' arcsin ' a mathematical function that is the inverse of the sine function.

Therefore, arcsin (x) is called the inverse sine function.

It is the angle whose sine is the number x.

So here we require angle in degree for which the Sine is '0'.

It is also written as

\sin^{-1}x

We Know that

\sin 0\°=0\\or\\\sin 180\°=0

Therefore,

\arcsin (0) = 0\°\\or\\\arcsin (0) = 180\°

Also integer multiples of 180° will have

\arcsin (0)=n\times 180\°

Where n = integer

Therefore for '0' we can have 2×180° , 3×180° , 4×180°....and so on i.e 360° , 540° and so on

Therefore,

The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.

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How do I solve this equation? I need a refresher on Algebra.
yaroslaw [1]
These equations seem tricky, but aren't as hard as you think. Just solve it like you are regularly adding fractions.

Your common denominator is 9x + 9, so

1/(9x+9)  =  36/(9x + 9)   -    (5x + 5)/9

1 - 36 + 5x + 5 / 9x - 9
30x - 30/9x - 9
10x-10/3x - 3
10(x-1)/3(x-1)
10/3

Hope this helped!
5 0
3 years ago
If you subtract 1/2 from a no. And multiply the result by 1/2, you get 1/8. What is the no.? ​
Bad White [126]

Answer:

no = 3/4

Step-by-step explanation:

1/2(no-1/2)=1/8

1/2no - 1/4 = 1/8

1/2no = 1/8 + 1/4

1/2no = 3/8

no = 3/4

8 0
3 years ago
A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect
Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

6 0
4 years ago
Please help me out here :))
mars1129 [50]

Answer:

no. i mean if u wanna take my points ok thats fine but dont be upset when i take ur points

Step-by-step explanation:

4 0
3 years ago
Write 0.4% as a fraction
gizmo_the_mogwai [7]
\frac{0,4}{100} = \frac{0,2}{50}= \frac{0,1}{25}= \frac{1}{250}
Hope that helps.Have a nice day!! ^^
8 0
3 years ago
Read 2 more answers
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