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3 years ago

Write 0.4% as a fraction

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

$\frac{0,4}{100} = \frac{0,2}{50}= \frac{0,1}{25}= \frac{1}{250}$
Hope that helps.Have a nice day!! ^^

VMariaS [17]3 years ago

7 0

$\boxed{0.4= \frac{0.4}{100}} \\ -------$

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3 years ago

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iVinArrow [24]

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The standard deviation of the scores on a recent exam is 6.

The sample size required is 25.

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Let X = scores of students on a recent exam.

It is provided that the random variable X is normally distributed.

According to the Empirical rule, 99.7% of the normal distribution is contained in the range, μ ± 3σ.

That is, P (μ - 3σ < X < μ + 3σ) = 0.997.

It is provided that the scores on a recent exam were normally distributed with a range from 51 to 87.

This implies that:

P (51 < X < 87) = 0.997

So,

μ - 3σ = 51...(i)

μ + 3σ = 87...(ii)

Subtract (i) and (ii) to compute the value of σ as follows:

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(-)μ + (-)3σ = (-)87

______________

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σ = 6

Thus, the standard deviation of the scores on a recent exam is 6.

The (1 - α)% confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error of this interval is:

$MOE = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Given:

MOE = 2

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Confidence level = 90%

Compute the z-score for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a z-table.

Compute the sample required as follows:

$MOE = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\2=1.645\times \frac{6}{\sqrt{n}}\\n=(\frac{1.645\times 6}{2})^{2}\\n=24.354225\\n\approx 25$

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3 years ago