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PSYCHO15rus [73]
3 years ago
14

Which part of the cell membrane can catalyze chemical reactions

Biology
2 answers:
lora16 [44]3 years ago
8 0

Answer:

Enzymes

Explanation:

APEX

Vsevolod [243]3 years ago
3 0

The correct answer is:  " enzymes " .

______________________________________________

Note that "enzymes" are "biological catalysts" .

______________________________________________

       "Catalysts" are agents that 'increase the rate of' , or 'speed up' , a 'chemical reaction' , when added to the reactants;  and by definition, catalysts do so within affecting the reaction itself.

       As aforementioned, "enzymes" can function as "biological catalysts" — which means that enzymes within the cell membrane can 'speed up' , or 'increase the rate of' , biological reactions (i.e. biochemical reactions) — without affecting the biological reaction (i.e. biochemical reaction) itself.

_____________________________________________

Hope this helps you!

Wishing you well in your academic pursuits —

      and within the "Brainly" community, as well!

_____________________________________________

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Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet
mina [271]

Answer:

5.7 m/s     

Explanation:

The computation of Sheila 's velocity right after she gets thrown out of the bike is shown below:

1) The Physical principle: conservation of momentum.

If there is no net external force operating on a system, so the system's total momentum is conserved

The momentum, p, is a vector magnitude that is determined as the product of the mass by the velocity:

P = mv.

2) Taking into account therefore that there is no net force on the device, Sheila and the momentum of the bike are the identical pre and post collision.

Based on this, the calculation is as follows

Momentum before the collision:

       P_1 = (mass\ of\ Sheila + mass\ of\ the\ bike) \times velocity

       P_1 = (60kg + m) \times v_1

= 340 kg m/s

Now Momentum after the collision:

      P_2 = mass\ of\ sheila \times velocity\ of\ Sheila + mass\ of\ the\ bike \times velocity\ of\ the\ bike

P_2 = 60kg \times v_2 + m \times 0 = 60kg \times v_2

P_1 = P_2

= (60kg + m) \times v_1

= 60kg \times v_2

= 340 kg .\ m/s

= 60kg \times v_2

v_2 =  \frac{340\ kg .\ m/s }{60\ kg}

= 5.7 m/s     

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