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Setler [38]
3 years ago
9

A copy machine was purchased for $35,000. The machine is estimated to have a useful life of four years with a residual value of

$3,000. It is estimated that the machine will make 2,000,000 copies. Using the units-of-activity method to depreciate the copy machine, what information is needed to calculate the first year's depreciation if 550,000 copies were made?
(A) $8,750
(B) $8,000
(C) $8,800
(D) $32,000
Business
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

(C) $8,800

Explanation:

Total Cost of Machine = $35,000

Salvage Value = $3,000

Value to be Depreciated = $35,000 - $3,000 = $32,000

Using units of activity method, we have copies to be made by machines = 2,000,000

Depreciation per copy = $32,000/2,000,000 = $0.016 per copy

Depreciation for year 1 = Number of copies \times $0.016

= 550,000 \times $0.016 = $8,800

Final Answer

(C) $8,800

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Answer:

The journal entry is as follows:

Cash A/c Dr. $ 25,437.50

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4 years ago
A man has $245,000 invested in three properties. One earns 12%, one 10% and one 8%. His annual income from the properties is $23
astraxan [27]

Answer:

for 8% investment = $110000

for 12% investment = $55000

for 10% investment =  $80000

annual income for each property is

x amount for 8% investment = $8800

y amount for 12% investment = $6600

z amount for 10% investment = $8000

Explanation:

Given data

investment = $245000

rate 1 = 12%

rate 2 = 10%

rate 3 = 8%

annual income = $23400

rate = 8%  twice that invested at 12%

to find out

invested in each property and  the annual income from each property

solution

let us consider x amount for 8% investment

and consider y amount for 12% investment

and consider z amount for 10% investment

from question we say,  8% is twice that invested at 12%

x = 2y      ........1

and

x + y + z = 245000      .............2

put 1 in equation 2

2y + y + z = 245000  

z = 245000 - 3y            ...................3

and we can say that

0.08x + 0.12y + 0.10z = 23400              ...........................4

put equation 1 and 3 in 4

0.08(2y) + 0.12y + 0.10( 245000 - 3y ) = 23400

0.16y + 0.12y - 0.3y = -1100

0.02y = 1100

y = $55000

so x = 2(y) = 2(5500) = $110000

and z = 245000 - 3(55000) = $80000

so annual income for each property is

x amount for 8% investment = 0.08 × 110000 = $8800

y amount for 12% investment = 0.12 × 55000 = $6600

z amount for 10% investment = 0.10 × 80000 = $8000

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