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SCORPION-xisa [38]
3 years ago
8

one data is in memory the computer interpets and executeinstructions to process the data into informationA. TrueB. False

Computers and Technology
1 answer:
lidiya [134]3 years ago
4 0

Answer:

Option A is the correct answer for the above question.

Explanation:

  • The computer is a system that processes the data to produce information. For any computer system when the data is processed then it will form the information.
  • The user gives some instruction to process that can also be called the program. Then the computer takes the instruction and processes the data on behalf of the instruction and for the information because in any system when data is processed it can form the information.
  • The above question says that the computer follows the instruction to process the data to produce the information which is correct as described above. Hence True is the correct answer to the above question.
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A tower or mini tower pc is a type of all- in -one unit true or false
Svetlanka [38]

Answer:

thx

Explanation:

5 0
3 years ago
Read 2 more answers
1000base-t is a standard for achieving throughputs ____ times faster than fast ethernet over copper cable.
meriva
An Average of 10 times faster.

Hope this helps!
3 0
3 years ago
Consider sending a 10000-byte datagram into a link that has an MTU of 4468 bytes. Suppose the original datagram is stamped with
AfilCa [17]

Answer:

Number of fragments is 3

Explanation:

The maximum size of data field in each fragment = 4468 - 20(IP Header)

= 4448 bytes

Hence, the number of required fragment = (10000 - 20)/4448

= 3

Fragment 1

Id = 218

offset = 0

total length = 4468 bytes

flag = 1

Fragment 2

Id = 218

offset = 556

total length = 4468 bytes

flag = 1

Fragment 3

Id = 218

offset = 1112

total length = 1144 bytes

flag = 0

5 0
2 years ago
Which algorithm makes the most efficient use ofmemory?
SashulF [63]

Answer:

Best-fit Algorithm

Explanation:

Best-fit: Allocating the smallest memory location that is greater than or equal to the size of process.

<u>Example</u>

Let these are the memory locations-210kb,310kb,260kb,610kb

                    and size of processes-160kb,450kb,250kb,300kb

For the first-fit,

We allocate 160 kb to the 210kb memory location

Then, we allocate 450 kb to the 610kb because others don't have the size.

Then,we allocate 250kb to the 310 kb.

300 kb will stop,as no memory locations can execute.

For the Best-fit,

We allocate 160 kb to the 210kb memory location

Then,we allocate 450kb to the 610kb.

Then,we allocate 250kb to the  260kb not 310kb according to best-fit.

Then we allocate 300kb to the 310kb.

For the worst fit,

We allocate 160 kb to the 610kb memory location according to the worst-fit algorithm.

Then,we can't allocate 450kb to any memory location.

Then,we allocate 250kb to the 310kb .

We can' allocate 300kb in 260kb memory location.

As we can see from this example that in First-fit algorithm 300kb process will stop as no memory location is there.

In worst-fit algorithm ,We can't allocate 450kb,300kb to any memory locations.

In Best-fit algorithm,we can allocate the process to each location,so this algorithm is using memory in a efficient way.    

5 0
3 years ago
I WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST AND CORRECTLY.
bogdanovich [222]

Answer:

True

Explanation:

3 0
3 years ago
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