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Andrej [43]
3 years ago
5

A circle has a diameter of 14cm. What's the circumfrence?

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
I believe that when finding the radius of a circle you half the diameter, but when finding the circumference of a circle you need to multiply the diameter (14cm) by pi.

So 14xpi= 43.98229715

But it can be simplified/ rounded to 44cm.

Of course I might be incorrect so do please correct me if I am wrong.
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Using appropriate properties find: 2/3 × 3/4 + 3/7 × 3/4​
Viktor [21]

Answer:

\frac{23}{28}

Step-by-step explanation:

\frac{2}{3}  \times  \frac{3}{4}  +  \frac{3}{7}  \times  \frac{3}{4}

=  >  \frac{3}{4} ( \frac{2}{3}  +  \frac{3}{7} )

=  >  \frac{3}{4}  \times  \frac{23}{21}

Reducing 3 from numerator and denominator,

=  >  \frac{23}{4 \times 7}  =  \frac{23}{28}

3 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
If RSTU is a rhombus, find the measure of angle RUT.
Schach [20]

<u>Finding x:</u>

We know that the diagonals of a rhombus bisect its angles

So, since US is a diagonal of the given rhombus:

∠RUS = ∠TUS

10x - 23 = 3x + 19                      [replacing the given values of the angles]

7x - 23 = 19                                [subtracting 3x from both sides]

7x = 42                                       [adding 23 on both sides]

x = 6                                           [dividing both sides by 7]

<u>Finding ∠RUT:</u>

We can see that:

∠RUT = ∠RUS + ∠TUS

<em>Since we are given the values of ∠RUS and ∠TUS:</em>

∠RUT = (10x - 23) + (3x + 19)

∠RUT = 13x - 4

<em>We know that x = 6:</em>

∠RUT = 13(6)-  4

∠RUT = 74°

8 0
3 years ago
HELPPPP
krek1111 [17]

Answer:

12.60

Step-by-step explanation:

To find the tip, take the amount of the bill and multiply by 30%

42 * 30%

Change to decimal form

42 * .30

12.6

3 0
3 years ago
Read 2 more answers
Which equation describes a line perpendicular to the line described by y= 1/2x -5?
Aneli [31]

Answer:

y= 2/1x -5

Step-by-step explanation:

flip it!

7 0
3 years ago
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