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harkovskaia [24]
3 years ago
15

What is the value of x

Mathematics
2 answers:
Lilit [14]3 years ago
3 0

Answer:

4

Step-by-step explanation:

For the first triangle which is triangle <KJL

Hypotenuse= 8✓2

Angle=30°

Opposite = ?

Therefore we will use Sine formula

Sin30° = Y/8✓2

Y=4✓2

For the second triangle which is triangle <JML

Hypotenuse= 4✓2

Opposite=X

Angle=45°

Therefore we will use Sine formula again

Sin45°=X/4✓2

X=4

Natali [406]3 years ago
3 0

Answer:

<h2>             x = 4</h2>

Step-by-step explanation:

ΔJKL is half of equilateral triangle and ΔJML is half of square.

We can use properties of these triangles (picture):

m∠KJL=90° and m∠JKL = 30° ⇒  JL = 0.5KL = 0.5•8√2 = 4√2

m∠JML=90° and m∠MJL = 45° ⇒  JL = ML√2

                                                        4√2 = x√2

                                                             x = 4

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(a) Consider a class with 30 students. Compute the probability that at least two of them have their birthdays on the same day. (
Galina-37 [17]

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a.) 0.7063

b.) 23

Step-by-step explanation:

a.)

Let X be an event in which at least 2 students have same birthday

     Y be an event in which no student have same birthday.

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P(X) + P(Y) = 1

⇒P(X) = 1 - P(Y)

as we know that,

Probability of no one has birthday on same day = P(Y)

⇒P(Y) = \frac{365!}{(365)^{n} (365-n)! }      where there are n people in a group

As given,

n = 30

⇒P(Y) = \frac{365!}{(365)^{30} (365-30)! } = \frac{365!}{(365)^{30} (335)! } = 0.2937

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P(X) = 1 - 0.2937 = 0.7063

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The probability that at least two of them have their birthdays on the same day  =  0.7063

b.)

Given, P(X) > 0.5

As

P(X) + P(Y) = 1

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As

P(Y) = \frac{365!}{(365)^{n} (365-n)! }

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