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KatRina [158]
3 years ago
14

Factor completely 3x^5-75x^3=

Mathematics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

\huge\boxed{3x^5-75x^3=3x^3(x-5)(x+5)}

Step-by-step explanation:

3x^5=3\cdot x^{3+2}=3\cdot x^3\cdot x^2=\boxed{3x^3}\cdot x^2\\\\75x^3=25\cdot\boxed{3x^3}\\\\3x^5-75x^3=3x^3(x^2-25)=3x^3(x^2-5^2)\\\\\text{Use}\ a^2-b^2=(a-b)(a+b)\\\\=3x^3(x-5)(x+5)

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\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

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If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

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Answer:

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Step-by-step explanation:

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