Question

In a video game, two objects move around the screen according to the equations r = 4cos(0) and r= -1 +

Answer 1

Answer:

The correct option is;

$\left ( -2,\dfrac{2 \cdot \pi }{3} \right)$

Step-by-step explanation:

The given parameters are

The equation of motion of one (the first) object is r = 4·cos(θ)

The equation of motion of the other (the second) object is r = -1 + 2·cos(θ)

Equating both equations gives;

4·cos(θ) = -1 + 2·cos(θ)

4·cos(θ) - 2·cos(θ) = -1

2·cos(θ) = -1

cos(θ) = -1/2

θ = Arccos(-1/2) = 120° = 2·π/3

Therefore, the two equations are equal when θ = 2·π/3 for which we have;

r = 4·cos(2π/3) = -2 and r = -1 + 2·cos(2π/3) = -2

∴ r = 4·cos(2π/3) = -1 + 2·cos(2π/3) = -2

The coordinate that represents a possible collision point of the objects in the form (r, θ) is therefore $\left ( -2,\dfrac{2 \cdot \pi }{3} \right)$

Answer 2

Answer:

A

Step-by-step explanation:

edg21 on the unit test