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Andru [333]
3 years ago
10

A’B’C’ is a dilation image of ABC. Which is the correct description of the dilation?

Mathematics
2 answers:
Papessa [141]3 years ago
8 0
It’s D hope I helped
klemol [59]3 years ago
4 0

Answer: center b and scale factor 3

Step-by-step explanation:

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4
inn [45]

Answer:

120

100+5w=m (m is his money after saving up)

4 0
3 years ago
Plz find the slope plzzzz
e-lub [12.9K]

Answer:

The slope would be rise over run so you go from point A and rise 4 then go over 8

So 4/8, then to simplify this it would be 1/2, so your slope is 1/2

Step-by-step explanation:

3 0
3 years ago
A sample of 100 cans of peas showed an average weight of 14 ounces with a standard deviation of 0.7 ounces. If the distribution
Roman55 [17]
This is an example of a normal distribution. An average weight is 14 ounces and a standard deviation is 0.7 ounces.
14.7 = 14 + 0.7 = Average + 1 Standard Deviation.
It means that the percent of cans that will weigh over 14.7 ounces is:
100% - ( 50 % + 34 % ) = 100% - 84% = 16%
16% of 100 cans:  16/100 * 100 = 16.
Answer: 16 cans. 
8 0
3 years ago
Read 2 more answers
The sides of a triangular plot are in the ratio of 3 : 5 : 7 and its perimeter is 300 m. Find its area. (Use 3 = 1.73)
eduard

Answer:

2598 units²

Step-by-step explanation:

Sum the parts of the parts of the ratio 3 + 5 + 7 = 15 parts

Divide the perimeter by 15

300 ÷ 15 = 20 ← value if 1 part, thus sides of triangle are

3 × 20 = 60

5 × 20 = 100

7 × 20 = 140

Using Hero's formula to calculate the area

A = \sqrt{s(s-a)(s-b)(s-c)}

where s is the semi perimeter and a, b , c are the sides of the triangle

s = 300 ÷ 2 = 150

let a = 60, b = 100 and c = 140, then

A = \sqrt{150(150-60)(150-100)(150-140)}

   = \sqrt{150(90)(50)(10)}

   = \sqrt{6750000} ≈ 2598 units²

7 0
3 years ago
Ngl i forgot whats 23+41
hoa [83]
64 is the answer and apparently it needs to be longer than 20 characters
3 0
3 years ago
Read 2 more answers
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