Question:
Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.
Answer:
1. the longer frame (B) has the shorter width
2. the shorter width is 6 3/7 inches, area divided by length
Step-by-step explanation:
The relation between area, length, and width is ...
A = LW
Then the width is ...
W = A/L . . . . . inversely proportional to length
1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.__
2. The width of frame B is ...
W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in
-Alan Becker
Answer:35t
Step-by-step explanation:
T=35
The answer is d) none because substituting -1/4x + 5/3 for y in the first equation gives 3x - 3x + 5/3 = 20 so 5/3 = 20 which is not true.
In this problem WP means what percent
20 = WP X 160
solve for WP, by dividing both sides by 160
and you get:
0.125 = WP
Change your decimal into a percent by multiplying by 100%
12.5% is your result.
