The woman is 61.5 inches tall.
This question is essentially asking for how many standard deviations the woman's height is away from the mean men's height.
Only 1 in 400 (or 0.25%) of men is shorter than our picky homegirl. If you think of a normal distribution of men's heights, this is the extreme left tail end. As a rule of thumb, +/- 3 standard deviations around the mean captures 99.5% of a population, leaving 0.5% outside of the interval (so, only 0.25% on each end). So we know that our girl refuses to marry anyone lower than -3 standard deviations from the mean.
All that's left is to plug in the given mean and SD:
69 -3(2.5) = 61.5 inches
Answer: Choice A) 5x^3 - x - 3
=================================================
Work Shown:
We subtract the two functions like so
(f - g)(x) = f(x) - g(x)
(f - g)(x) = ( 5x^3-2 ) - ( x+1 )
(f - g)(x) = 5x^3 - 2 - x - 1
(f - g)(x) = 5x^3 - x - 3 ..... choice A
Note: be sure to remember to distribute the negative to every term inside (x+1), and not just to the x only.
Answer:
x=-5
Step-by-step explanation:
Answer:
We conclude that the area of the right triangle is:
Hence, option A is correct.
Step-by-step explanation:
From the given right-angled triangle,
Using the formula to determine the area of the right-angled triangle
Area of the right triangle A = 1/2 × Base × Perpendicular
Factor 2p-6: 2(p-3)
Divide the number: 2/2 = 1
Therefore, we conclude that the area of the right triangle is:
Hence, option A is correct.