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Anuta_ua [19.1K]
3 years ago
11

What is the surface area of a circle that has a diameter of 14 inches

Mathematics
2 answers:
Anna007 [38]3 years ago
8 0
The area of any circle is        (pi) · (radius)² .

The radius is 1/2 of the diameter.

For your circle, the radius is 1/2 of 14 inches  =  7 inches,
and the area is

                            (pi) · (7 inches)²

                         = (pi) · (49 square inches)

                         =      153.9 square inches  (rounded)
fgiga [73]3 years ago
7 0
A= 153.94in squared
Hope I helped :)
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3 years ago
Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4
Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

First convert the mixed fraction to improper fraction

15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}

So the area of 1st rectangle is

A_1 = 12\times \frac{61}{4} = 183 \: in^{2}

He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}

10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}

So the area of 2nd rectangle is

A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}

The total construction paper needed for this project is

A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}

Therefore, Dennis need 288.91 square inches of construction paper for his project.

6 0
4 years ago
Draw and identify the coordinates of the image of the figure after a 180° rotation
sladkih [1.3K]

Answer:

Step-by-step explanation:

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5 0
4 years ago
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Cos 52º=______
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7 0
4 years ago
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Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
4 years ago
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