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Gnom [1K]
3 years ago
5

This water tank is made from a cylinder cone what is the volume of the tank HELP PLEASE

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

A

Step-by-step explanation:

it might be the answer but I don't know for sure. SORRY

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First, I add 1. Then, I multiply by 2. Next, I divide by 3. As a result, I get 4. What is my starting number?
Ira Lisetskai [31]

Answer:5

Step-by-step explanation:

reverse the steps

2(x+1)/3=4

2(x+1)/3×3=4×3

2(x+1)/2=12/2

x+1=6

x=6-1

x=5

6 0
3 years ago
Read 2 more answers
HELP ASAP PLS AHHHHHH
Arada [10]

Answer:

23 tables were used that day at lunch.

Step-by-step explanation:

203 - 19 = 184

184 ÷ 8 = 23

3 0
3 years ago
There are a total of 15 dimes and quarters in a covered cup. The value of all 15 coins totals 2.85
QveST [7]

Answer:

There are 6 dimes and 9 quarters.

Step-by-step explanation:

Represent the number of dimes and the number of quarters by d and q.

Then d + q = 15, or q = 15 - d.

Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.

Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or

75 - 5d + 2d = 57, or

75 - 3d = 57, or

3d = 18.  Thus, there are 6 dimes.  Since q = 15 - d, q = 15 - 6 = 9.

There are 6 dimes and 9 quarters.

6 0
3 years ago
What is the correct answer..
solong [7]

Answer:

64 feet

Step-by-step explanation:

To find the height of the kite we use sin trigonometric ratio.

Let the height of the kite from the ground be x feet.

\therefore \: \sin 40 \degree =  \frac{x}{100}  \\  \\  \therefore \: 0.6427876097=  \frac{x}{100}  \\  \\ \therefore \: 0.6427876097 \times 100= x \\  \\  \therefore \:x = 64.29  \\  \\  \therefore \:x = 64 \: feet

3 0
3 years ago
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
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