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egoroff_w [7]
3 years ago
5

2 096 to the nearest 1000

Mathematics
2 answers:
k0ka [10]3 years ago
6 0
The answer to this is 2000...
hope this helps and HAGD!
laila [671]3 years ago
4 0
2096 rounds down to 2000.
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The answer would be 6.45
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In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the
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Answer:

P(t) = 5100e^{0.0039t}

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

P(t) = P(0)e^{rt}

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that P(0) = 5100

So

P(t) = 5100e^{rt}

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that P(5) = 5200.

We use this to find r.

P(t) = 5100e^{rt}

5200 = 5100e^{5r}

e^{5r} = \frac{52}{51}

\ln{e^{5r}} = \ln{\frac{52}{51}}

5r = \ln{\frac{52}{51}}

r = \frac{\ln{\frac{52}{51}}}{5}

r = 0.0039

So the equation for the moose population is:

P(t) = 5100e^{0.0039t}

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3 years ago
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I believe it is 16/7 or 2 2/7

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We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

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a_1 = 1st term of sequence,

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n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

a_n=1\cdot (7)^{n-1}

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where n\geq 1.

4 0
4 years ago
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