About 3% of the population has a particular genetic mutation. 600 people are randomly selected.
1 answer:
Answer:
<em>Standard deviation for the number of people with the genetic mutation = 4.178</em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given random sample size 'n' =600
proportion of the Population 'p'=3% or 0.03
Let 'X' be the random variable in binomial distribution
Mean of the binomial distribution
μ = n p
= 600 X 0.03
= 18
<em>Mean of the binomial distribution ' μ ' =18</em>
<em>Standard deviation of the binomial distribution</em>
<em> σ = </em>
<u><em>Conclusion:</em></u><em>-</em>
<em>Standard deviation for the number of people with the genetic mutation = 4.178</em>
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Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year
<h3><u>Solution:</u></h3>Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.
Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively
Also, his annual return totaled $144
We can form following equation on the basis of question:-
a = $800
The amount of money invested at 6% = a = 800
The amount of money invested at 4 % = 3a = 3(800) = 2400
So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400