Answer: y = 4km + 2km*x
Step-by-step explanation:
We know that Madelyn already cycled 4km this year, so we start at that point.
Now, each time that she goes to work, she cycles 2 km in total.
Now, if she does x trips to work, then she cycles 2km x times, this means that in total she would cycle 2km*x
if we also count the 4km she already has, we have the linear equation:
y = 4km + 2km*x
This is the equation we wanted to get.
Answer:
I would the answer is x^6+1
Step-by-step explanation: First you add X^2 +x^4=X^6
than you add the 2/3 and the 1/3 which simpflies to 1
Answer:p=$20
Step-by-step explanation:
145-65=80
80/4=20
so each pant costs $20
p=$20
If Rhonda has 140 points, you would want to subtract 30 from her score to get 110 and then divide by two to get mark’s score. Your final answer would be 55
Answer:
<h2><em><u>2nd</u></em><em><u> </u></em><em><u>Option</u></em><em><u>:</u></em></h2>
![\frac{1}{ {a}^{42} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%7Ba%7D%5E%7B42%7D%20%7D%20)
Step-by-step explanation:
![{( {r}^{ - 7}) }^{6}](https://tex.z-dn.net/?f=%20%7B%28%20%7Br%7D%5E%7B%20-%207%7D%29%20%7D%5E%7B6%7D%20)
<em><u>Since</u></em><em><u>,</u></em>
![{( {a}^{x}) }^{y} = {a}^{xy}](https://tex.z-dn.net/?f=%20%20%7B%28%20%7Ba%7D%5E%7Bx%7D%29%20%7D%5E%7By%7D%20%20%3D%20%20%7Ba%7D%5E%7Bxy%7D%20)
<em><u>Then</u></em><em><u>,</u></em>
![= {r}^{ (- 7 \times 6)} = {r}^{ - 42}](https://tex.z-dn.net/?f=%20%3D%20%20%7Br%7D%5E%7B%20%28-%207%20%5Ctimes%206%29%7D%20%20%3D%20%20%7Br%7D%5E%7B%20-%2042%7D%20)
<em><u>Since</u></em><em><u>,</u></em>
![{a}^{ - 1} = \frac{1}{a}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20-%201%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7Ba%7D%20)
<em><u>Then</u></em><em><u>,</u></em>
![= {r}^{ - 42} = \frac{1}{ {r}^{42} }](https://tex.z-dn.net/?f=%20%3D%20%20%7Br%7D%5E%7B%20-%2042%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B%20%7Br%7D%5E%7B42%7D%20%7D%20)
<em><u>Therefore</u></em><em><u>, </u></em>
<em><u>2nd</u></em><em><u> </u></em><em><u>Option</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u>. </u></em>