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3 years ago

Tiffany wanted belgian waffles for breakfast while on her dream vacation.

Mathematics

2 answers:

krek1111 [17]3 years ago

5 0

Answer:

A) belgian

Step-by-step explanation:

Belgian is a proper noun

egoroff_w [7]3 years ago

4 0

Answer: a

Step-by-step explanation: its definitly not d becuse you cannot capitilize it in the middle of a sentence/and its not waffles (the same reason) and i do not think its vacation

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a) How many significant figures are in the numbers 99 and 100? (b) If the uncertainty in each number is 1, what is the percent u

levacccp [35]

Answer:

2, 3

1.01, 1

Percentage uncertainty

Step-by-step explanation:

a) The significant figures in the number 99 is 2

The significant figures in the number 100 is 3

b) Uncertainty in each of the numbers for both the numbers is 1

Percentage uncertainty

$\text{Percentage uncertainty}=\frac{\text{Uncertainty}}{Value}\times 100 \\\Rightarrow \text{Percentage uncertainty}=\frac{1}{99}\times 100=1.01$

Percentage uncertainty = 1.01

100

$\text{Percentage uncertainty}=\frac{\text{Uncertainty}}{Value}\times 100 \\\Rightarrow \text{Percentage uncertainty}=\frac{1}{100}\times 100=1$

Percentage uncertainty = 1

c) Percentage uncertainty is a better way to express the numbers as the significant figures do not show the actual value of the numbers.

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3 years ago

A recipe of chicken and rice calls 3 1/2 pounds of chicken. Lisa want to adjust the recipe so that it yields 1 1/2 times as much

anzhelika [568]

3 1/2 is equal to 7/2. 1 1/2 is equal to 3/2. 7/2 times 3/2 is equal to 21/2, which is equal to 10 1/2.

7 0

3 years ago

A high school had 2,300 students in 2010 which increased by 33% in the following four years. How many students are there in 2014

mr Goodwill [35]

Students in 2014 = (100% + 33%) × 2,300
students in 2014 = 133% × 2,300
students in 2014 = 133/100 × 2,300
students in 2014 = 3,059

There are 3,059 students in 2014

4 0

3 years ago

Simplify 5.47+2.758+12.3

-Dominant- [34]

Answer:

20.528

Step-by-step explanation:

8 0

3 years ago

A cat gave birth to 3333 kittens who each had a different mass between 147147147147 and 159 g159\,\text{g}159g159, start text, g

harina [27]

Answer:

The correct option is (B).

Step-by-step explanation:

The median (m) is a measure of central tendency. To obtain the median, we assemble the data in arising order. If the data is odd, the median is the mid-value. If the data is even, the median is the arithmetic-mean of the two mid-values.

The mean of a data set is:

$\bar X=\frac{1}{n}\sum\limits^{n}_{x=0}{X}$

For the three kittens it is provided that the weights are in the range 147 g to 159 g.

So, the mean and median weight for the 3 kittens lies in the middle of this range.

Now a fourth kitten is born, with weight 57 g.

Now the range of the weight of 4 kittens is, 57 g to 159 g.

The mean is going to decrease as one more value is added to the data and the value is the least.

The median will also decrease because now the median will be mean of the 2nd and 3rd values.

But the mean would decrease more than the median because a smaller value is added to the data.

Thus, the correct option is (B).

5 0

3 years ago