A pyramid has a square base that is 160 m on each side. What is the perimeter of the base in kilometers? Question 19 options:

Mathematics

1 answer:

vekshin12 years ago

8 0

Answer:

0.64 kilometres

Step-by-step explanation:

Step 1: Find the perimeter in metres

Perimeter of square = 4 x (Length)

Perimeter = 4 (160)

Perimeter = 640 metres

Step 2: Convert from metre to kilometre

1 km = 1000 m

x km = 640 m

Cross multiply

1000x = 640

x = 0.64 kilometres

Therefore, the perimeter of the square base is 0.64 kilometres.

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How do work this out

BabaBlast [244]

We can factor this by using grouping. Take the leading coefficient and multiply it by the constant. In this case we get 5*-7 = -35.

Now we need 2 numbers that add to 2 and multiply to be -35. The numbers are -5 and 7.

So split the 2r into these two terms and group.

(5r^2 - 5r) + (7r - 7)

Factor both groups.

5r(r-1) + 7(r-1)

The factors of (r-1) can be added together to get the answer.

(r-1)(5r+7)

6 0

3 years ago

+7p – 1 – p + 5 expression is simpliest form

Yuki888 [10]

Answer:

6p + 4

Step-by-step explanation:

7p - 1 - p + 5

~Combine like terms

6p + 4

Best of Luck!

8 0

2 years ago

The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.

saveliy_v [14]

The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°

the answer is
angle BAD=104°