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Natali [406]
3 years ago
15

The difference of 2 numbers is 20 and their product is 125

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
4 0

Answer:

The two numbers are ;

<h2>x = 25</h2><h2>y = 5</h2><h3>I Hope It Helps :)</h3>

Step-by-step explanation:

Let -the -unknown- numbers-be-x-and-y\\x-y =20    (1)\\xy = 125   (2)\\On -equation (1) make-x -the- subject-of-the-formula\\x  = 20+y\\Substitute, 20+y in- equation- for x\\y(20+y)=125\\20y +y^{2} =125\\Arrange-in-general-form-of-a-quadratic-equation=\\ax^{2} +bx +c =0\\y^{2} +20y-125=0\\Using -factorization -method\\Find-two-factors- when - added- give +20 and -when- multiplied give-125\\Factors=+25y and  -5y\\y^{2} +25y-5y-125=0\\factorize- y -out \\y(y+25)-5(y+25)=0\\(y+25)(y-5)=0\\

(y+25)=0- or -(y-5)=0\\y = 0-25  -or- y = 0+5\\y = -25 , y= 5\\ y- cannot -have- a- negative- value \\y = 5\\substitute 5 for y in equation (1) -or-(2)\\x-y = 20    (10\\x-5 = 20 \\x = 20 +5\\x = 25

Semenov [28]3 years ago
3 0

Answer:

ans= 25, 5

Step-by-step explanation:

Guess a number that you can the difference as 20 and when you multiply you get 125. For imstance in my case the difference between 25 and 5 is 20 and their product is 125

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Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
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slavikrds [6]

Answer:

a = 10, b = 6, c = 2, d = 0

Step-by-step explanation:

Substitute the appropriate values of x into the equation and evaluate

x = - 3 : y = 4 - 2(- 3) = 4 + 6 = 10 → a

x = - 1 : y = 4 - 2(- 1) = 4 + 2 = 6 → b

x = 1 : y = 4 - 2(1) = 4 - 2 = 2 → c

x = 2 : y = 4 - 2(2) = 4 - 4 = 0 → d

5 0
2 years ago
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Answer:

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