Question

A production process operates with 3% nonconforming parts. Every hour a sample of 50 parts is taken, and the number of nonconforming parts counted. If one or more nonconforming parts are found, the process is stopped and the quality control technician must search for the cause of nonconforming production. What is the probability that the process is stopped?

Answer 1

Answer: The required probability is 0.782.

Step-by-step explanation:

Since we have given that

Probability of non conforming parts = 3%

Number of parts is taken = 50

Probability of conforming parts = 100-3=97%

So, using Binomial distribution, we get that

Probability that the process is stopped is given by

$P(X\geq 1)=1-P(X=0)=1-^{50}C_0(0.03)^0(0.97)^{50}\\\\P(X\geq 1)=1-0.218\\\\P(X\geq 1)=0.782$

Hence, the required probability is 0.782.