Is there a picture or something?
Ur outlier is 21
mean is : 5
deviation is 2.6
so ur answer is : 2nd one
Answer: -31
<u>Step-by-step explanation:</u>
f(x) = -x⁴ + 3x³ + x² - 8x - 16
f(3) = -(3)⁴ + 3(3)³ + (3)² - 8(3) - 16
= -81 + 81 + 9 - 24 - 16
= -31
Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%