Answer:
a) 580 - 16n
b) 9850 - 271.72n
Step-by-step explanation:
a) starting number of bales = 580
each day, the farmer feeds out 2 bales of hay to each yard. he has 8 yards, so he feeds out 2 bales 8 times for a total of 2 * 8 = 16 bales. Therefore, he loses 16 bales each day
After the first day, he has 580-16 = 564 bales. After the second, he has 564-16 = 548 bales, and so on. He loses 16 bales n times for n days, and as a result, his final amount of bales is
original amount - amount lost = 580 - 16n
b)
First, we can calculate how much a bale weighs.
average = sum/count = 9850 kg / 580 ≈ 17 kg
Therefore, as he loses 16 bales of hay, he loses 17 kg 16 times, or approximately 271.72 kg of hay every day. For n days, he loses 271.72n kg. This brings his final amount to be
starting - amount lost = 9850 - 271.72n
1.) 12x^2-7x-10
2.) 10x^2+31x-14
Answer:
XY = 8 and YZ = 20
Step-by-step explanation:
If XY and YZ are on the one line, we can write
XY + YZ = 28
(2x+2) + (9x - 7) = 28
2x+2 + 9x - 7 = 28
11x - 5 = 28
11x = 33
x = 3
XY = 2x+2 = 2*3 + 2 = 8
YZ = 9x - 7 = 9*3 - 7 = 27 - 7 = 20
Answer:
See below
Step-by-step explanation:
The first one 'cubes' the denominator AND the numerator:
(-2/5)^3 = -2/5 * -2/5 * -2/5 = -8/125
The second one 'cubes' only the denominator:
-2/5^3 = -2 / (5 * 5 * 5) = - 2 / 125
