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Andreas93 [3]
3 years ago
5

What is the area of this parallelogram?

Mathematics
2 answers:
yan [13]3 years ago
8 0

Answer:

5.8

Step-by-step explanation:

Ber [7]3 years ago
3 0
The answers is D because when finding area you have to times length by width.
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What is the degree of x^4-3x+2<br> A.3<br> B.2<br> C.4<br> D.5
Viktor [21]
The answer is C.

Look at all the exponents for the x's. What is the highest exponent? It's 4, making this a 4th degree polynomial.
5 0
3 years ago
B) Write 1.74 x 10^4 as an ordinary number.
astra-53 [7]

Answer:

17400

Step-by-step explanation: i might get this wrong but just do 1.74*10^4 and it should equal 17400

6 0
3 years ago
What is the volume of the square pyramid shown to the nearest tenth? The figure is not drawn to scale. width of 16 and a length
valentinak56 [21]

Answer:

1450.67

Step-by-step explanation:

V=a^2 x h/3

7 0
4 years ago
Read 2 more answers
Homework 1:Pythagorean Theorem and it’s Converse<br><br> Find The Value of X
Viefleur [7K]

The figure gives a dimension for the hypotenuse of 19

the height is given as 17, using the Pythagorean theorem we can find the base of the triangle:

19^2 = 17^2 + base^2

Simplify:

361 = 289 + base^2

Subtract 289 from both sides:

72 = base^2

Take the square root of both sides:

Base = 8.49 Round to 8.5

There are two identical triangles on each sides, so 8.5 x 2 = 17

The length of the two triangle bases is 17

The total base of the object is 31, so the length of the rectangular part in the middle would be 31 - 17 = 14

And X would be the same length as the bottom rectangle.

Therefore x = 14

3 0
3 years ago
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What is the interquartile range of the following data set? 78,90,456,676,111,381,21
kodGreya [7K]

Answer

The IQR of the data set is 368.

Explanation

To find the interquartile range, you first need to find the median of the data set. Then, you find the median of the median and subtract them. This might be a little confusing but I'll walk through everything.

First, put the data set in order from least to greatest; 21 78 90 111 381 456 676. Find the median. The median of this data set is 111, since it is the middle number when the data set is ordered from least to greatest.

To find the Q1 and Q3 of the set, you have to find the median of the median.

The set right now is 21 78 90 111 381 456 676. Remove the 111 (if there were an even amount of numbers in the set, you wouldn't remove the 111 and you would just split the data set in half). Now you have two sets: 21 78 90 and 381 456 676. The median of the first set is 78 (this is the Q1) and the median of the second set is 456 (this is the Q3).

To find the interquartile range, subtract the Q1 from the Q3. 456-78=368.

3 0
3 years ago
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