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worty [1.4K]
4 years ago
13

In a recent survey of middle school students about pizza toppings, it was found that 25 students like pepperoni pizza,31 like ba

nana peppers and 5 like both pepperoni and banana peppers on their pizza.If 66 students were surveyed,how many do not like banana peppers on their pizza?
Mathematics
1 answer:
Gemiola [76]4 years ago
8 0

35 students did not like banana peppers on their pizza.

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What is 92÷30 has an mixed number
Kipish [7]

Answer:

  • 3 2/30.

Step-by-step explanation:

<u>Given equation:</u>

  • 92 ÷ 30

<u>Solve for remainder:</u>

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<u>Convert it to a fraction:</u>

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2 years ago
(a + b)² = a² + 2ab + b2 with step by step explanation​
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Step-by-step explanation:

Given: (a+b)²

To prove: (a+b)² = a² + 2ab + b²

Proof:-

(a+b)² = (a+b)(a+b)

(a+b)²=a(a+b)+b(a+b)

(a+b)² = a²+ab+ab+b²

(a+b)² = a²+2ab+b².

3 0
3 years ago
A line has an x-intercept of 3 and a y-intercept of -6. The slope-intercept form of its equation is
Rufina [12.5K]
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The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 8 golfer
dexar [7]

Answer:

The 90% confidence interval to estimate the average difference in scores between the two courses is (-1.088, 20.252).

Step-by-step explanation:

We have the standard deviation for the differences, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.8946

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.8946\frac{15.9274}{\sqrt{8}} = 10.67

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 9.582 - 10.67 = -1.088

The upper end of the interval is the sample mean added to M. So it is 9.582 + 10.67 = 20.252

The 90% confidence interval to estimate the average difference in scores between the two courses is (-1.088, 20.252).

3 0
3 years ago
Miss Robin distributed a bag of skittles to her students she gave each student five skittles then ate the 8 that remained in the
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Answer:

27

Step-by-step explanation:

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3 years ago
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