Answer:
Yes.
Step-by-step explanation:
You can find it out by factoring but ill do it easier way.
(x + 1 ) = 0 put the first and second equation to 0
x = -1
x³ + 2x² - 5x - 6 = 0 Now plug in the x in the equation
(-1)³ + 2(-1)² - 5(-1) - 6 = 0
0 = 0
so (x + 1) is a factor.
Answer:
@Genius102 has answered this already, but here it is
Step-by-step explanation:
a) the scale should go by 1,000 because that would show that the slope is growing by time.
b) the intervals should go by 500 because 18,500 is the last number, so it should be 500
25 is the answer/ third option
<u>Differentiate using the Quotient Rule</u> –
![\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\](https://tex.z-dn.net/?f=%5Cpink%7B%5Ctwoheadrightarrow%20%5Csf%20%5Cdfrac%7Bd%7D%7Bdx%7D%20%5Cbigg%5B%5Cdfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%20%5Cbigg%5D%3D%20%5Cdfrac%7B%20g%28x%29%5C%3A%5Cdfrac%7Bd%7D%7Bdx%7D%5Cbigg%5Bf%28x%29%5Cbigg%5D%20-f%28x%29%5Cdfrac%7Bd%7D%7Bdx%7D%5C%3A%5Cbigg%5Bg%28x%29%5Cbigg%5D%7D%7Bg%28x%29%5E2%7D%7D%5C%5C)
According to the given question, we have –
- f(x) = x^3+5x+2
- g(x) = x^2-1
Let's solve it!
![\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\](https://tex.z-dn.net/?f=%5Cgreen%7B%5Ctwoheadrightarrow%20%5Cbf%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cbigg%5B%20%5Cdfrac%7Bx%5E3%2B5x%2B2%20%7D%7Bx%5E2-1%7D%5Cbigg%5D%7D%20%5C%5C)
