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4 years ago

What is the area? (IXL)

Mathematics

2 answers:

algol134 years ago

7 0

Answer:

A = 72

Step-by-step explanation:

The formula for the area of a trapezoid is: $A=\frac{a+b}{2}h$

a and b represents the 2 bases

h is the height

Using the formula:

$A=\frac{a+b}{2}h =\frac{6+10}{2}9=8*9=72$

The area should be 72 square inches.

Serga [27]4 years ago

4 0

Answer:

(6+10)*9

then divide by 2

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Answer:

BOTH SIDES ARE 12

Step-by-step explanation:

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3 years ago

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PLEASE HELP ME OH LORD <br> Evaluate (4/25)^1/2

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(4/25)^1/2 =

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3 years ago

Hector had 30 minutes to do a three-problem quiz. He spent 11 3 4 minutes on question A and 6 1 2 minutes on question B. How muc

stich3 [128]

Answer:

$11 \frac{3}{4}$ min

Step-by-step explanation:

In order to solve this problem, we must subtract the times he has already used from the time he has available, so we get:

$30-11 \frac{3}{4} - 6 \frac{1}{2}$

we can start solving this subtraction by turning all of the numbers into improper fractions so we get:

$\frac{30}{1}-\frac{11*4+3}{4}- \frac{6*2+1}{2}$

$\frac{30}{1}-\frac{47}{4}- \frac{13}{2}$

next, we can find a least common denominator. In this case it will be 4, so we need to turn all denominators into a 4, so we get:

$\frac{30*4}{1*4}-\frac{47}{4}- \frac{13*2}{2*2}$

$\frac{120}{4}-\frac{47}{4}- \frac{26}{4}$

and now we can subtract the numerators and copy the denominators so we get:

$\frac{120-47-26}{4}$

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which can now be turned into a mixed number by dividing 47/4 which yields 11 with a remainder of 3, so the mixed number is:

$11 \frac{3}{4}$ min

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3 years ago

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

kow [346]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that $n = 292, \pi = \frac{52}{292} = 0.178$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207$

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

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3 years ago