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Neko
[114]
3 years ago
8
how many liters of a 10% silver iodide solution must be mixed with 3 L of a 4% silver iodine solution to get s 6% solution?
Mathematics
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answer:
Vikentia
[17]
3 years ago
4
0
To answer this problem, you should just substitute some figures in order to get the required amount.
So, let a be the amount of 10% iodide solution
So...
4 (3) + 10a = 6 (3+a)
[4 represents the silver iodine solution, the 3 is the liters, while we are looking for the 6% solution]
12 + 10a = 18 + 6a
10a - 6a = 18 - 12
4a = 6
a = 6/4
a = 3/2
So you will need 3/2 or 1.5 liters of 10% iodide solution.
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