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4 years ago

how many liters of a 10% silver iodide solution must be mixed with 3 L of a 4% silver iodine solution to get s 6% solution?

1 answer:

4 0

To answer this problem, you should just substitute some figures in order to get the required amount.

So, let a be the amount of 10% iodide solution

So...

4 (3) + 10a = 6 (3+a)
[4 represents the silver iodine solution, the 3 is the liters, while we are looking for the 6% solution]

12 + 10a = 18 + 6a

10a - 6a = 18 - 12

4a = 6

a = 6/4
a = 3/2

So you will need 3/2 or 1.5 liters of 10% iodide solution.

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I need the answers for this question

nekit [7.7K]

Answer:

13/12 or 1 1/12

Step-by-step explanation:

First you would convert the 1/6 to 2/12 then add them like normal to get 13/12.

Hope this helps :

5 0

3 years ago

Consider this scaled figure of a swimming pool. The dimensions of the original pool are 24 feet wide by 36 feet long. A rectangl

kozerog [31]

The scale factor used for scaling the actual rectangular pool was 4/15 and the length of the scaled rectangle is 9.6 feet.

<h3>How to calculate the scale factor?</h3>

Suppose the initial measurement of a figure was x units.

And let the figure is scaled and new measurement is of y units.

Since the scaling is done by multiplication of some constant, that constant is called scale factor. Let that constant be 's'.

Then we have:

$s \times x = y\\s = \dfrac{y}{x}$

Thus, scale factor is the ratio of the new measurement to the old measurement.

For this case, we're specified that:

Dimensions of the original pool = 24 feet wide by 36 feet long

The scaled rectangle's dimension: 6.4 feet width and L feet length (we assume the length be L units).

So, in scale drawing, 24 feet was converted to 6.4 feet. Let the scale factor be 's', then:

$6.4 = s \times 24\\\\s = \dfrac{6.4}{24} = \dfrac{4}{15}$

Thus, since length is also scaled by same factor(as the whole figure is scaled by constant scale factor assumingly), we get:

Scaled length = s times original length

$L = \dfrac{4}{15} \times 36 = 9.6 \: \rm feet$

Thus, the scale factor used for scaling the actual rectangular pool was 4/15 and the length of the scaled rectangle is 9.6 feet.

Learn more about scale factors here :

brainly.com/question/8765466

5 0

2 years ago

90,95,101,98,103,119,124,123,132,127 what is the mean

lana66690 [7]

To find the mean, you add all of the numbers and divide by how many they are. When you add them you get 1112, then divide by 10 and get...

answer: 111.2

4 0

3 years ago

The answer has to be simplified

OLga [1]

Answer:

m = 2

Step-by-step explanation:

m m+3

----- = ----------

4 10

Using cross products

10m = 4(m+3)

Distribute

10m = 4m+12

Subtract 4m from each side

10m-4m = 4m-4m+12

6m = 12

Divide by 6

6m/6 = 12/6

m = 2

3 0

3 years ago

Read 2 more answers

-3|9x-7|=2 Find the answer for x

labwork [276]

<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

No Solutions

<h3>Step-by-step explanation:</h3>

Given:

$-3|9x -7| = 2$

Rewriting the given equation:

$-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}$

We have to realize that the right side of the equation, $|9x -7|$ , will always be positive no matter what real values of $x$ (because we're taking the absolute value of the expression) and we are equating it to a negative constant number, $-\frac{2}{3}\\$ . Something that is always positive will never be negative so there's no value for $x$ that satisfies the solution.

$\rule{6.5cm}{0.5pt}$

You may not read the following passage that I have written.

$\rule{6.5cm}{0.5pt}$

Solving by positive of the expression:

$9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}$

Solving by the negative of the expression:

$-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\ 9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}$

Checking: $x = \frac{19}{27}\\$

$-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{19}{27}\\$ is an extraneous solution.

Checking: $x = \frac{23}{27}\\$

$-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{23}{27}\\$ is an extraneous solution.

8 0

3 years ago