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LenaWriter [7]
3 years ago
13

Write the equation of the line which passes through (2, –1) and is perpendicular to the line with equation 5y – x = 1.

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
Solve 5y - x = 1 for y such that y = mx + b so we can extract the slope.
y = 1/5x + 1/5
Perpendicular lines have opposite signed reciprocal slopes.
1/5 would have an opposite signed (-) reciprocal (5) slope of -5

Now let's find b by substituting the values of y, m, and x into y = mx + b:
-1 = -5(2) + b
-1 = -10 + b
9 = b
So the equation is y = -5x + 9 or 5x + y = 9
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The student council is planning for the prom. They have broken down their expenses in the graph below. If they decide they will
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Answer:

D

Step-by-step explanation:

1200=30%

1200/x=30%

1200*.3=400

400=x

6 0
3 years ago
How can a mixed number be written as a sum?
k0ka [10]
First, write the mixed number as a sum of a whole number and a proper fraction. Then write the two parts with common denominator , and add. Once you're used to this, you can use a shortcut method: 1) Multiply the whole part by the denominator of the fractional part, and add the numerator of the fractional part.
8 0
3 years ago
A data set has a normal distribution with a mean of 47 and a standard deviation of 4.6. Use this information to scale the horizo
gulaghasi [49]

Horizontal axis with 1, 2, and 3 standard deviations above the mean are 51.6, 56.2, 60.8

Horizontal axis with 1, 2, and 3 standard deviations below the mean are 42.4, 37.8, 33.2

<u>Step-by-step explanation:</u>

A data set has a normal distribution with a mean of 47 and a standard deviation of 4.6

  • Mean, M ⇒ 47
  • Standard deviation ⇒ 4.6

From this information, you have to scale the horizontal axis with the mean of this distribution and values at 1, 2, and 3 standard deviations above and below the mean.

Horizontal axis with 1, 2, and 3 standard deviations above the mean :

1 standard deviation above the mean ⇒ M + SD

⇒ 47 + 4.6 = 51.6

2 standard deviations above the mean ⇒ M + 2SD

⇒ 47 + (2 × 4.6) = 56.2

3 standard deviations above the mean ⇒ M + 3SD

⇒ 47 + (3 × 4.6) = 60.8

Horizontal axis with 1, 2, and 3 standard deviations below the mean :

1 standard deviation below the mean ⇒ M - SD

⇒ 47 - 4.6 = 42.4

2 standard deviations below the mean ⇒ M - 2SD

⇒ 47 - (2 × 4.6) = 37.8

3 standard deviations below the mean ⇒ M - 3SD

⇒ 47 - (3 × 4.6) = 33.2

8 0
3 years ago
Would the hypotenuse of a right triangle with a vertical length of 6 and a horizontal length of 10 have the same slope as the hy
Elodia [21]
No

1. Vertical 6, horizontal 10
6/10 = 3/5 slope

2. (Red) vertical -2, horizontal 3
-2/3 does not equal 3/5

3. (Blue) vertical 4, horizontal 6
4/6 = 2/3 but does not equal 3/5
3 0
3 years ago
What is 2x^2-x-15 in vertex form
In-s [12.5K]

Answer:

(1/4,-121/8)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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