Pls help me with this one 1,2,3,4
2 answers:
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Answer:
2
Step-by-step explanation:
The first equation is that of a an ellipse. The second equation is that of a line.
Attached is the graphs of both of these equations.
<em>If you think about it, there can only be 2 possible ways of solutions (intersection points) of an ellipse and a line.</em>
<em>1. The line will not intersect the ellipse at all, so no solution</em>
<em>2. The line will intersect the ellipse at 2 points maximum</em>
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So, we can clearly see from the reasoning that the maximum number of possible solutions would be 2. The graph attached confirms this as well.
General Idea:
The angles which occupy the same relative position at each intersection where a straight line crosses two others. If the two lines are parallel, the corresponding angles are equal.
The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles. The theorem says that when the lines are parallel, that the alternate interior angles are equal.
Applying the concept:
Angles PBC and BAD are congruent by the <u>Corresponding Angle Theorem</u>.
Angles ABC and BAT are congruent by the <u>Alternate Interior angle Theorem</u>.
