Answer:
The time it takes to boil 2.2 litres of water is approximately 141 seconds
Step-by-step explanation:
The given parameters are;
The relationship of the variables, T and A is a proportional, therefore, we have;
T ∝ A, or T/A = k = Constant of proportionality
The time it takes to boil 2.8 liters of water = 180 seconds
∴ When A = 2.8 litres, T = 180 seconds, from which we have;
k = T/A = 180 s/(2.8 L) = 450/7 s/L
k = 450/7 s/L
When A = 2.2 litres, we have;
T/A = k
∴ T = k × A
Plugging in the value for both 'k', and 'A' when A = 2.2 litres, gives;
T = k × A = 450/7 s/L × 2.2 L = 990/7 s = 141.
s
The time it takes to boil 2.2 litres of water, given a direct proportionality relation is, T = 141. seconds ≈ 141 seconds given to the nearest second.
Answer:
its 13 if i saw the numbers right
Step-by-step explanation:
evaluate then you get the below
1-(-4)x(-3)+12/(-6)
___________
-1
divide and get;
-(1-(4)x(-3)+12/(6))
remove parentheses and divide
-(1+4x(-3)-2)
multiply and get
-(1-12-2)
calculate
-(-13)
remove "()"
and you get 13
<h3>
is the recursive formula of the geometric sequence</h3>
<em><u>Solution:</u></em>
<em><u>Given geometric sequence is:</u></em>
-0.6, 3 , -15, 75
We have to frame the recursive formula
Find the common ratio
Thus common ratio is -5
<em><u>The nth term of geometric sequence is given as:</u></em>
Where,
n is the nth term
a is the first term of sequence
r is common ratio
From sequence,
a = -0.6
r = -5
Therefore,
Where, n = 1 , 2 , 3 , 4 , .....
Thus the recursive formula is found
The answer to this question would be: <span>D) square inches</span>
In this question, Alex needs to find the surface area of a shoe box. Surface area unit would be represented by "square" because it is 2 dimension. The unit "cubic" is used for volume which was 3 dimension. From here, the option A and C is out because it uses cubic.
The inch unit is better since it was smaller than feet. If you using feet square, the area of the shoe box will be small and it might be less accurate than using inch.
X is the variable
its possible values are the domain of the expression
