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andriy [413]
3 years ago
8

If you are given the graph of g, how could you

Mathematics
2 answers:
vlabodo [156]3 years ago
8 0

Answer: Add 3 to the Y-coordinate

Step-by-step explanation:

vladimir2022 [97]3 years ago
6 0

Answer: Add 3 to the y-coordinate

Step-by-step explanation:

You might be interested in
Scores turned in by an amateur golfer at a golf course during 2017 and 2018 are as follows.
SSSSS [86.1K]

Answer:

For 2017 Season:

Mean = 75

Standard deviation = 2.07

For 2018 Season:

Mean = 75

Standard deviation = 5.26

Step-by-step explanation:

The following formulas will be used in these calculations:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

Where;

n = number of values = 8

x = each value

For 2017 Season

Mean = (73 + 77 + 78 + 76 + 74 + 72 + 74 + 76) / 8 = 600 / 8 = 75

Variance = ((73-75)^2 + (77-75)^2 + (78-75)^2 + (76-75)^2 + (74-75)^2 + (72-75)^2 + (74-75)^2 + (76-75)^2) / (8-1) = 30 / 7 = 4.29

Standard deviation = Variance^0.50 = 4.29^0.5 = 2.07

For 2018 Season

Mean = (70 + 69 + 74 + 76 + 84 + 79 + 70 + 78) / 8 = 75

Variance = ((70-75)^2 + (69-75)^2 + (74-75)^2 + (76-75)^2 + (84-75)^2 + (79-75)^2 + (70-75)^2 + (78-75)^2) / (8-1) = 194 / 7 = 27.71

Standard deviation = Variance^0.50 = 27.71^0.5 = 5.26

4 0
3 years ago
HELP ILL GIVE BRAINLIEST determine the range of the following graph:
AleksandrR [38]

Answer:

(-2, 10]

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The scores of fourth grade students on a mathematics achievement test follow a normal distribution with a mean of 75 and standar
mamaluj [8]

Answer:

The appropriate solution is:

(a) 0.1056

(b) 0

(c) 0.9544

Step-by-step explanation:

The given values are:

Mean,

\mu = 75

Standard deviation,

\sigma = 4

(a)

⇒  P(x>80)=1-(x

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P[\frac{x-\mu}{\sigma}

                     =1-P(z

By using the table, we get

                     =1-0.8944

                     =0.1056

(b)

According to the question, the values are:

n = 64

\mu_\bar{x} = 75

Now,

⇒  \sigma_\bar{x} = \frac{\sigma}{\sqrt{n} }

         = \frac{4}{\sqrt{64} }

         = \frac{4}{8}

         = 0.5

⇒  P(\bar {x} >80 ) = 1 - P(\bar x

                      =1 - P[\frac{(\bar x-\mu_\bar x)}{\sigma \bar x} < \frac{80-75}{0.5}  ]

                      =1-P(z

By using the table, we get

                      =1-1

                      =0

(c)

As we know,

⇒ \sigma_\bar x = \frac{\sigma}{\sqrt{n} }

        = \frac{4}{\sqrt{64} }

        = \frac{4}{8}

        = 0.5

then,

= P(74< \bar x

= P[\frac{74-75}{0.5} < \frac{\bar x-\mu \bar x}{\sigma \bar x} < \frac{76-75}{0.5} ]

= P(-2

= P(z

By using the table, we get

= 0.9772-0.0228

= 0.9544

7 0
3 years ago
I is more than the product of 7 and s​
Marysya12 [62]

Answer:

i is an imaginary number

3 0
3 years ago
Jeo is comparing the price of different boxes of cereal. One box has 16 oz. and costs $3.50. Another costs $3.89 for a 24 oz. bo
velikii [3]

Answer:

The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

Step-by-step explanation:

☆Let's solve using proportion.

☆One box:

\frac{16 \: oz.}{3.50 \: dollars}  =  \frac{1 \: oz.}{x}  \\  \\  \frac{3.50}{16}  =  \frac{16x}{16 }  \\  \\ 0.22 = x

☆Another box:

\frac{24 \: oz.}{3.89 \: dollars}   = \frac{1 \: oz.}{x }  \\  \\  \frac{3.89}{24}  =  \frac{24x}{24}  \\ \\ x = 0.16

☆All we need to do is subtract: 0.22 - 0.16 = 0.06

☆The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

7 0
3 years ago
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