If you are given the graph of g, how could you
2 answers:
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Answer:
Attachment 1 :- x = 3/2
Attachment 2 :- m + r = 154°
Step-by-step explanation:
Attachment 1 :-
As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-
Attachment 2 :-
PQR is a straight line . It's given that m + n = 110°
But we know that m + n + r = 180° ..............eqn.1
So substituting the value of m+n in eqn.1 gives :-
m+n+r = 180°
=> r + 110° = 180°
=> r = 180° - 110°
= 70°
It's also given that n+r = 96°
So putting the value of r in the above gives ,
n+r = 96°
=> n + 70° =96°
=> n = 96° - 70°
= 26°
Putting the value of n in eqn.1 gives
m + n = 110°
=> m + 26° = 110°
=> m = 110° - 26°
= 84°
So m + r = 84° + 70° = 154°
Answer:
C.
Step-by-step explanation:
p(x)=sin(x) is an odd function since sin(-x)=-sin(x).
q(x)=cos(x) is an even function since cos(-x)=cos(x).
r(x)=tan(x) is an odd function since tan(-x)=-tan(x).
s(x)=csc(x) is an odd function since csc(-x)=-csc(x).
So the only contender seems to be C.
Let's check. To check we have to plug in (-x) in place of (x) and see if we get the same function back since we are looking for an even function.
Replace (x) with (-x):
since cosine is even; that is cos(-u)=cos(u) where u in this case is
.
So f is even.
