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3 years ago

What is the slope-intercept equation of the line below?

Mathematics

2 answers:

kumpel [21]3 years ago

6 0

Answer:

4/1.5

Step-by-step explanation:

Dmitrij [34]3 years ago

4 0

Answer:

it’s either 3 or 1/3

Step-by-step explanation:

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

Please help! I need help with this question.

musickatia [10]

Answer:

Step-by-step explanation:

the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.

8 0

3 years ago

Need help asapppp!!! plz i will give brainliest to the person with the correct answer

max2010maxim [7]

Answer:

Multiply x by 4 and make x negative if it's positive or make x positive if it's negative.

Step-by-step explanation:

Multiplying x by a number greater than 1 will stretch the parabola.

Changing x from positive to negative and vice versa reflects the parabola over the x-axis.

8 0

2 years ago

The world's largest university (by enrollment) is University A, followed by University B. If the enrollment in University A i

Sav [38]

Let x be the number of people at University B

x + (x+3.5) = 9.5
2x +3.5 = 9.5
2x = 6
x = 3 million students at University B

x + 3.5 = 3 + 3.5 = 6.5 million students at University A

8 0

3 years ago

Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200

Virty [35]

Answer:

work done is equal to 384279168 lb-ft

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as $\pi r^{2} h$

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = $3.142* 7^{2}*200$ = 30791.6 ft^3

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = 1921395.84 lb

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> work done is equal to 384279168 lb-ft

7 0

3 years ago

What is the slope-intercept equation of the line below?​

What is the slope-intercept equation of the line below?