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AlekseyPX
3 years ago
15

Express in scientific notation. Remember, M must be a number such that 1 ≤ M < 10. 0.00000000000013 = _____ .

Mathematics
2 answers:
Talja [164]3 years ago
6 0

Answer:

0.00000000000013 = 1.3 x 10^-13 the answer is c

Step-by-step explanation:

monitta3 years ago
6 0

Answer:

Option c - 0.00000000000013=1.3\times 10^{-13}

Step-by-step explanation:

Given : Expression M must be a number such that 1 ≤ M < 10. 0.00000000000013

To find : Express in scientific notation ?

Solution :

Scientific notation is the form of writing number in smaller term using multiple of 10.

Number - 0.00000000000013

There is decimal place before 14 numbers.

So, 0.00000000000013=13\times 10^{-14}

In scientific notation the decimal is placed after tenth.  0.00000000000013=1.3\times 10^{-13}

Therefore, Option c is correct.

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Select the functions that have identical graphs.
Elan Coil [88]

Answer:

c. 1 and 3

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot each equation.

Please see the attached image below, to find more information about the graph

s

The equations are:

1) y = sin (3x + π/6)

2) y = cos (3x - π/6)

3) y = cos (3x - π/3)

Looking at the graphs, we can see that the identical ones

are equations one and three

Correct option:

c. 1 and 3

3 0
3 years ago
Can u help me plssss
Anastaziya [24]

Answer:

120 I think.

Step-by-step explanation:

Because 10*12=120

3 0
3 years ago
Read 2 more answers
Marine biologists have been studying the effects of acidification of the oceans on weights of male baluga whales in the Arctic O
PSYCHO15rus [73]

Answer:

c. 61.25 kg

Step-by-step explanation:

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.

a. 15.31 kg

b. 51.40 kg

c. 61.25 kg

d. 80.49 kg

Margin of Error Formula= z × Standard deviation/√n

95% confidence interval = 1.96

Standard deviation = 125kg

n = 16 samples

Margin of error= 1.96 × 125/√16

= 1.96 × 125/4

= 245/4

= 61.25kg

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg

6 0
3 years ago
The graph shows the relationship between time and distance is Pam rides her bike. During which time period was the rate of chang
tensa zangetsu [6.8K]
Where is the graph ?
4 0
3 years ago
Read 2 more answers
Graph y = 3(x + 2)3 - 3 and describe the end behavior.
-BARSIC- [3]
1) The function is 3(x + 2)³ - 3

2) The end behaviour is the limits when x approaches +/- infinity.

3) Since the polynomial is of odd degree you can predict that the ends head off in opposite direction. The limits confirm that.

4) The limit when x approaches negative infinity is negative infinity, then the left end of the function heads off downward (toward - ∞).

5) The limit when x approaches positive infinity is positivie infinity, then the right end of the function heads off upward (toward + ∞).

6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.


7) x-intercepts ⇒ y = 0

⇒ <span>3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0
</span>

<span>⇒ (x + 2)³ = -1 ⇒ x + 2 =  1 ⇒ x = - 1
</span>

8) y-intercepts ⇒ x = 0

y = <span>3(x + 2)³ - 3 = 3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 = 21
</span><span>
</span><span>
</span><span>9) Critical points ⇒ first derivative = 0
</span><span>
</span><span>
</span><span>i) dy / dx = 9(x + 2)² = 0
</span><span>
</span><span>
</span><span>⇒ x + 2 = 0 ⇒ x = - 2
</span><span>
</span><span>
</span><span>ii) second derivative: to determine where x = - 2  is a local maximum, a local  minimum, or an inflection point.
</span><span>
</span><span>
</span><span>y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.
</span><span>
</span><span>
</span><span>Then the function does not have local minimum nor maximum, but an inflection point at x =  -2.
</span><span>
</span><span>
</span><span>Using all that information you can graph the function, and I attache the figure with the graph.
</span>


3 0
3 years ago
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