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3 years ago

Express in scientific notation. Remember, M must be a number such that 1 ≤ M < 10. 0.00000000000013 = _____ .

Mathematics

2 answers:

Talja [164]3 years ago

6 0

Answer:

0.00000000000013 = 1.3 x 10^-13 the answer is c

Step-by-step explanation:

monitta3 years ago

6 0

Answer:

Option c - $0.00000000000013=1.3\times 10^{-13}$

Step-by-step explanation:

Given : Expression M must be a number such that 1 ≤ M < 10. 0.00000000000013

To find : Express in scientific notation ?

Solution :

Scientific notation is the form of writing number in smaller term using multiple of 10.

Number - 0.00000000000013

There is decimal place before 14 numbers.

So, $0.00000000000013=13\times 10^{-14}$

In scientific notation the decimal is placed after tenth. $0.00000000000013=1.3\times 10^{-13}$

Therefore, Option c is correct.

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3 years ago

What is Discount Comics is running a special: 20 comics for $5.00. Seth purchases 30 comics for $7.50. What is the sale price pe

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3 years ago

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Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3

Basile [38]

Answer:

The mass of the steel ball is 4,235.9 gr

Step-by-step explanation:

Density

The density ρ of a substance is a measure of its mass per unit volume:

$\displaystyle \rho=\frac{m}{V}$

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

$m=\rho.V$

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

$\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3$

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

$\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3$

Calculating:

$V=523.6\ cm^3$

The mass is:

$m=8.09 gr/cm^3 \cdot 523.6\ cm^3$

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3 years ago

Solve the following equation 6x - 4 = 2 + 3x

Svetach [21]

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3 years ago

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Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

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1 year ago