Answer:
The speed of the jet is 347 mph and the speed of the wind is 18 mph.
Step-by-step explanation:
We have the following:
x = the speed of the jet in still air.
y = the speed of the wind
we know that the speed is equal to:
v = d / t
therefore the distance would be:
d = v * t
if we replace with the information of the exercise we have:
3 * (x + y) = 1095
3 * (x - y) = 987
we must solve this system of equations, add both equations and we are left:
3 * x + 3 * y = 1095
3 * x - 3 * y = 987
3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987
6 * x = 2082
x = 2082/6 = 347
now to calculate y, we replace:
3 * (347 + y) = 1095
1041 + 3 * y = 1095
3 * y = 1095 - 1041
y = 54/3 = 18
The speed of the jet is 347 mph and the speed of the wind is 18 mph.
Answer:
109.3 yard²
Step-by-step explanation:
Area of triangle = bh / 2
base is 23yd
height is 9.5yd
bh / 2 = 23 × 9.5 / 2
Area = 218.5 / 2
Area = 109.25 yd²; rounded to the nearest tenth is 109.3yd²
The first one is.
3 x 3A is oA
3 x 4 is +12
9a +12
1,1,2,3,5,8, ______, ______, _______, _________, _______.
jasenka [17]
12 20 32 52 84 hope I helped
Solution
Step 1:
Write the lateral surface area or curved surface area of a cylinder:
Step 2:
Write the given data
Height h = 8ft
Radius r = 4 ft
Step 3:
Substitute in the formula to find the lateral surface area.
Final answer
201.1
