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just olya [345]
3 years ago
6

The population of the world in 1987 was 5 billion and the annual growth rate was estimated at 2 percent per year. Assuming that

the world population follows an exponential growth model, find the projected world population in 1998.
Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

Population in 1998 year = 6.22 billion

Step-by-step explanation:

Given:-

- The population in year 1987, Po = 5 billion

- Growth rate, r = 2%

- World population follows an exponential growth model

Find:-

The projected world population in 1998.

Solution:-

- The exponential growth model is mathematically expressed as:

            Population in x year = Po* ( 1 + r/100)^( x - xo )

Where,   xo: The base year.

- Plug in the values and solve for the projected population in year 1998:

            Population in 1998 year = 5,000,000,000* ( 1 + 2/100)^( 1998 - 1987 )

            Population in 1998 year = 5,000,000,000* ( 1 + 0.02)^( 11 )

                                                     = 5,000,000,000* ( 1.02 )^( 11 )

                                                     = 6.22 billion                                

Novay_Z [31]3 years ago
5 0

Answer:

The projected world population in 1998 is 6,216,871,541.95

Step-by-step explanation:

Here we have the formula for exponential growth given by

A = P(1 + r)^t

Where:

A = Population at the end of the time period

P = Population at the start of the time period

r = Rate percent of population growth

t = Time period of interest

Therefore, given r = 2% = 2/100 = 0.02, P = 5,000,000,000;

t = year 1998 - year 1987 = 11 years

We have

A = 5,000,000,000 ×(1+0.02)^{11}= 6,216,871,541.95

≈ 6.2 billion.

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Irina-Kira [14]

Answer:

24 customers will not use coupons.

Step-by-step explanation:

Number of customers who use coupons = 9

Number of customers who don't use coupons = x

Ratio of customers who use coupons to customers who don't use coupons = 6:16

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3 years ago
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Basile [38]

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9

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3 0
3 years ago
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malfutka [58]

Answer:

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5 0
2 years ago
How many cubes with side lengths of \dfrac14\text{ cm}
bogdanovich [222]

Answer:

Step-by-step explanation:

Correct question

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3 years ago
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Westkost [7]

Answer: 8n

Let's simplify step-by-step.

(2(n+1)−1)2−(2n−1)2

Distribute:

=4n2+4n+1+−4n2+4n+−1

Combine Like Terms:

=4n2+4n+1+−4n2+4n+−1

=(4n2+−4n2)+(4n+4n)+(1+−1)

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7 0
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