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wolverine [178]
4 years ago
8

How do you find the least common multiple of these two expressions. 10x^5v^8 and 25x^4v^7u^2

Mathematics
2 answers:
RoseWind [281]4 years ago
8 0
10x^5v^8=5x^4v^7\cdot2xv\\\\25x^4v^7u^2=5x^4v^7\cdot5u^2\\\\LCM(10x^5v^8;\ 25x^4v^7u^2)=5x^4v^7\cdot2xv\cdot5u^2=50x^5v^8u^2
Ahat [919]4 years ago
4 0
10x^{5} v^{8}= 1*2*5*x*x*x*x*x*v*v*v*v*v*v*v*v \\ 25 x^{4} v^{7} u^{2}=1*5*5*x*x*x*x*v*v*v*v*v*v*v*u*u \\
Underline all the numbers which are common in both the factorisations. Write them down:
5 x^{4} v^{7}
There, you have your LCM of both the expressions.
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4 years ago
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A 4 meter long ladder leans against a 90 degree wall at a 68 degree angle.
Alenkinab [10]

Answer:

Step-by-step explanation:

We use trig to answer these questions:

sin x = opposite side of a triangle / hypotenuse

cos x = adjacent side / hypotenuse

Construct a right triangle with hypotenuse 4 m and lower angle 68 degrees.

The height of the top of the ladder  is then defined by:

sin 68 degrees = height / 4 m, which yields (4 m)(sin 68) = height =

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3 0
3 years ago
In a class, half of students had gone to watch magic show. Twice the square root of
love history [14]

Answer:

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3 0
3 years ago
Can someone please solve this
mote1985 [20]
That’s pretty easy you just have to basically y=mx+b
5 0
2 years ago
Hey there! posted picture of question help please
kakasveta [241]
For this case we have the following function:
 f (x) = (1/3) * (4 ^ x)
 We must evaluate the function for x = 2
 We have then:
 f (2) = (1/3) * (4 ^ 2)
 Rewriting:
 f (2) = (1/3) * (16)
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 Answer:
 
The function evaluated at x = 2 is:
 
f (2) = 16/3
 
option A
7 0
3 years ago
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