solution:
the change in the boiling point is given as,
dTbp =2.30°c
elevation constant for the solvent is given by,
kb=0.512°c/m
= 4.49m
Answer:
The answer is
2.79g
.Explanation:
mBaSO4=nBaSO4 ⋅ molarmass = 0.012moles ⋅ 233.3 g\mole = 2.79g
Hope this helps :)
The answer is C since both charge and mass have to be balanced on both sides of the equation.
Hello friend, the answer would be 1609.34. Hope it helps. :) BTW, I've also double checked for you. :)
Using the relationship M1V1 = M2V2 where M1 and M2 are the molar concentrations (mol/L or mmol/ml) and V1 and V2 are the volumes of the solutions, we can arrive at the following answer for the given problem:
<span>15.0M (L of stock solution) = 2.35M (0.25L) *all volumes were converted to liters.
L of stock solution = (2.35*0.25)/15.0
Therefore, 0.0392L or 39.17 ml of stock solution is needed. </span>