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frutty [35]
3 years ago
8

Calculate the pH of a 0.187 M solution of a base that has a Kb = 5.86x10^-6

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

pH=11

Explanation:

Hello there!

In this case, since the ionization of the described base is:

base+H_2O\rightarrow OH^-+baseH^+

Thus, the equilibrium expression in terms of the reaction extent is:

Kb=5.86x10^{-6}=\frac{x^2}{0.187-x}

Thus, by solving for x we obtain:

5.86x10^{-6}({0.187-x})=x^2\\\\1.10x10^{-6}-5.86x10^{-6}x-x^2=0

So the values of x are:

x_1=0.0010M\\x_2=-0.0010M

So the feasible answer is 0.0010 M, thus we compute the pOH:

pOH=-log(0.0010M)=3

And therefore the pH:

pH=14-pOH=14-3\\\\pH=11

Best regards!

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In an atom, the number of neutrons determines most specifically the ________.
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In an atom, the number of neutrons determines most specifically the isotopes of an element.

<h2>Further Explanation</h2><h3>An atom  </h3>
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<h3>Neutrons  </h3>
  • They are sub-atomic particles in an atom that are found in the nucleus of an atom. They have a zero charge or no charge.
  • Neutrons are slightly heavier than protons.
  • The number of protons and neutrons in a nucleus of an atom results to the atomic mass number of an atom. Like protons they only take part in nuclear reactions.
<h3>Protons</h3>
  • Protons are subatomic particles that are found in the nucleus of an atom. They are positively charged. with a charge of +1.
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  • The nucleus of an atom is positively charged due to the positive charge of the protons.  
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<h3>Electrons  </h3>
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Keywords: Atom, sub-atomic particles, electrons, protons, neutrons, isotopes  

<h3>Learn more about:</h3>
  • Sub-atomic particles: brainly.com/question/12762384
  • Electrons: brainly.com/question/1264222
  • Protons: brainly.com/question/1264222
  • Neutrons: brainly.com/question/1264222
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Level: High school

Subject: Chemistry  

Topic: Atomic structure

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Answer:

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Explanation:

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The required concentration of ethanol can be determined as follows:

=  ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}

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The chemical equation for the reaction of Californium-249 nucleus with Carbon-12 nucleus follows:

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