The salivary amylase did not perform well if the pH becomes lower because it needs neutral pH for performing its functions.
<h3>Effect of pH on the enzyme</h3>
We can say that the salivary amylase did not perform their function very well within the stomach due to unfavourable environment such as lower pH. Due to lower pH, the enzyme structure is damaged so unable to perform its function so we can conclude that the salivary amylase did not perform well if the pH becomes lower.
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Answer:
A double displacement reaction is a type of reaction in which two reactants exchange ions to form two new compounds. Double displacement reactions typically result in the formation of a product that is a precipitate.
Explanation:
I believe it was decomposition reaction
Answer:Increased the number of molecular collisions and increased the reaction rate
Explanation:
The pH of a 0.163 m aqueous solution of sulfurous acid is 1.28
<h3>
What is an Aqueous Solution?</h3>
Aqueous solution is defined as the type of solution which has a high solubility in water.
To obtain the ph of a 0.163 m aqueous solution of sulfurous acid, we would have to:
First construct the ICE table:
- H₂SO₃ --> H⁺ + HSO₃⁻
- I 0.163 M 0 0
- C - x + x + x
- E 0.163 - x + x + x
Next, we would have to express the acid dissociation of sulfurous acid:
![K_{a} = \frac{[H^{+} ][HSO_{3} ^{-} ]}{{H_{2} SO_{3} }}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%20%20%5D%5BHSO_%7B3%7D%20%5E%7B-%7D%20%5D%7D%7B%7BH_%7B2%7D%20SO_%7B3%7D%20%7D%7D)
By putting the values in equation :
{x²}{(0.163 - x)} = 1.7 x 10⁻²
{x²}{0.163} = 1.7 x 10⁻²
x = 0.052640 M
pH = 1.28.
Thus the pH of a 0.163 M aqueous solution of sulfurous acid is 1.28.
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