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3 years ago

What is the answer plz!!!! I Will mark brainliest!!!!!!

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Answer:

a. she doesnt have any points

b. just draw 3 circles with a plus in them

c. kiara has 7 points

d. -7+7=0

Step-by-step explanation:

mark me brainliest

you can mark me brainliest by clicking the crown at the bottom of this answer

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Kyle took out a seven-year loan of $8,000 loan from his bank. The bank charges an interest rate of 5 percent, compounded yearly.

Nookie1986 [14]

Assuming the loan is as described, seven-year loan, which means that Kyle does not repay a cent before seven years.

This is a compound interest problem where n=7 years, interest rate i=0.05, and present value P=8000.

At the end of seven years, Kyle will have to pay

Future value = F = P(1+i)^n = 8000(1.05)^7 = 11256.80 (to the nearest cent)

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Which results from a cross section made perpendicular to the base of a square pyramid? Check all that apply.

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ú The square-shaped slice can be made from a slice parallel to the base of a right rectangular prism, cube, and right rectangular pyramid with a square base. The triangle-shaped slice and isosceles trapezoid-shaped slice can be made with a slice made perpendicular to the base of a right rectangular pyramid. A pentagon-shaped slice cannot be made from a slice made parallel or perpendicular to the base of either a right rectangular prism, right rectangular pyramid, or cube.

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3 years ago

PLSSSS HELPPP I WILLL GIVEEE BRAINLIESTTTT!!!!!!!!!!!!!!!!!

agasfer [191]

Answer: use a slope calculator

-1/6

Step-by-step explanation:

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3 years ago

Let z=3+i, then find a. Z² b. |Z| c.<img src="https://tex.z-dn.net/?f=%5Csqrt%7BZ%7D" id="TexFormula1" title="\sq

zysi [14]

Given z = 3 + i, right away we can find

(a) square

z ² = (3 + i )² = 3² + 6i + i ² = 9 + 6i - 1 = 8 + 6i

(b) modulus

|z| = √(3² + 1²) = √(9 + 1) = √10

(d) polar form

First find the argument:

arg(z) = arctan(1/3)

Then

z = |z| exp(i arg(z))

z = √10 exp(i arctan(1/3))

z = √10 (cos(arctan(1/3)) + i sin(arctan(1/3))

Any complex number has 2 square roots. Using the polar form from part (d), we have

√z = √(√10) exp(i arctan(1/3) / 2)

and

√z = √(√10) exp(i (arctan(1/3) + 2π) / 2)

Then in standard rectangular form, we have

$\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right)\right)$

and

$\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right)\right)$

We can simplify this further. We know that z lies in the first quadrant, so

0 < arg(z) = arctan(1/3) < π/2

which means

0 < 1/2 arctan(1/3) < π/4

Then both cos(1/2 arctan(1/3)) and sin(1/2 arctan(1/3)) are positive. Using the half-angle identity, we then have

$\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}$

$\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}$

and since cos(x + π) = -cos(x) and sin(x + π) = -sin(x),

$\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}$

$\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}$

Now, arctan(1/3) is an angle y such that tan(y) = 1/3. In a right triangle satisfying this relation, we would see that cos(y) = 3/√10 and sin(y) = 1/√10. Then

$\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10+3\sqrt{10}}{20}}$

$\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10-3\sqrt{10}}{20}}$

$\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}$

$\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}$

So the two square roots of z are

$\boxed{\sqrt z = \sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}$

and

$\boxed{\sqrt z = -\sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}$

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3 years ago

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Volume? Correct answers please

goldfiish [28.3K]

Answer:

V = 1385.44

Step-by-step explanation:

The equation for volume is V = π r 2 h! Where V = volume, r = radius (half the diameter), and h = height. Now lets substitute what we know into this equation!

Since we are giving the diameter (14) we must divide by 2 to find the radius.

14 ÷ 2 = 7

Radius = 7

Height = 9

V = ?

Time to plug these values in!

V = π $7^{2}$ (9)

We have to distribute pi to 7 square that term and then multiply the value by 9.

V = 1385.44

Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

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3 years ago