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faust18 [17]
3 years ago
7

What is the answer plz!!!! I Will mark brainliest!!!!!!

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

a. she doesnt have any points

b. just draw 3 circles with a plus in them

c. kiara has 7 points

d. -7+7=0

Step-by-step explanation:

mark me brainliest

you can mark me brainliest by clicking the crown at the bottom of this answer

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Kyle took out a seven-year loan of $8,000 loan from his bank. The bank charges an interest rate of 5 percent, compounded yearly.
Nookie1986 [14]

Assuming the loan is as described, seven-year loan, which means that Kyle does not repay a cent before seven years.

This is a compound interest problem where n=7 years, interest rate i=0.05, and present value P=8000.

At the end of seven years, Kyle will have to pay

Future value = F = P(1+i)^n = 8000(1.05)^7 = 11256.80 (to the nearest cent)

7 0
3 years ago
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Which results from a cross section made perpendicular to the base of a square pyramid? Check all that apply.
Mamont248 [21]

<span>ú   </span>The square-shaped slice can be made from a slice parallel to the base of a right rectangular prism, cube, and right rectangular pyramid with a square base.  The triangle-shaped slice and isosceles trapezoid-shaped slice can be made with a slice made perpendicular to the base of a right rectangular pyramid.  A pentagon-shaped slice cannot be made from a slice made parallel or perpendicular to the base of either a right rectangular prism, right rectangular pyramid, or cube.

7 0
3 years ago
PLSSSS HELPPP I WILLL GIVEEE BRAINLIESTTTT!!!!!!!!!!!!!!!!!
agasfer [191]

Answer: use a slope calculator

-1/6

Step-by-step explanation:

4 0
3 years ago
Let z=3+i, <br>then find<br> a. Z²<br>b. |Z| <br>c.<img src="https://tex.z-dn.net/?f=%5Csqrt%7BZ%7D" id="TexFormula1" title="\sq
zysi [14]

Given <em>z</em> = 3 + <em>i</em>, right away we can find

(a) square

<em>z</em> ² = (3 + <em>i </em>)² = 3² + 6<em>i</em> + <em>i</em> ² = 9 + 6<em>i</em> - 1 = 8 + 6<em>i</em>

(b) modulus

|<em>z</em>| = √(3² + 1²) = √(9 + 1) = √10

(d) polar form

First find the argument:

arg(<em>z</em>) = arctan(1/3)

Then

<em>z</em> = |<em>z</em>| exp(<em>i</em> arg(<em>z</em>))

<em>z</em> = √10 exp(<em>i</em> arctan(1/3))

or

<em>z</em> = √10 (cos(arctan(1/3)) + <em>i</em> sin(arctan(1/3))

(c) square root

Any complex number has 2 square roots. Using the polar form from part (d), we have

√<em>z</em> = √(√10) exp(<em>i</em> arctan(1/3) / 2)

and

√<em>z</em> = √(√10) exp(<em>i</em> (arctan(1/3) + 2<em>π</em>) / 2)

Then in standard rectangular form, we have

\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right)\right)

and

\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right)\right)

We can simplify this further. We know that <em>z</em> lies in the first quadrant, so

0 < arg(<em>z</em>) = arctan(1/3) < <em>π</em>/2

which means

0 < 1/2 arctan(1/3) < <em>π</em>/4

Then both cos(1/2 arctan(1/3)) and sin(1/2 arctan(1/3)) are positive. Using the half-angle identity, we then have

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}

and since cos(<em>x</em> + <em>π</em>) = -cos(<em>x</em>) and sin(<em>x</em> + <em>π</em>) = -sin(<em>x</em>),

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}

Now, arctan(1/3) is an angle <em>y</em> such that tan(<em>y</em>) = 1/3. In a right triangle satisfying this relation, we would see that cos(<em>y</em>) = 3/√10 and sin(<em>y</em>) = 1/√10. Then

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10+3\sqrt{10}}{20}}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10-3\sqrt{10}}{20}}

\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}

\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}

So the two square roots of <em>z</em> are

\boxed{\sqrt z = \sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}

and

\boxed{\sqrt z = -\sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}

3 0
3 years ago
Read 2 more answers
Volume? Correct answers please
goldfiish [28.3K]

Answer:

V = 1385.44

Step-by-step explanation:

The equation for volume is V = π r 2 h! Where V = volume, r = radius <em>(half the diameter)</em>, and h = height. Now lets substitute what we know into this equation!

<em>Since we are giving the diameter (14) we must divide by 2 to find the radius.</em>

                         14 ÷ 2 = 7

Radius = 7

Height = 9

V = ?

Time to plug these values in!

V = π 7^{2} (9)

<em>We have to distribute </em><em>pi to 7 square that term </em><em>and then </em><em>multiply the value by 9</em><em>. </em>

<em />

V = 1385.44

Hope this Helps! :)

<em>Have any questions? Ask below in the comments and I will try my best to answer.</em>

-SGO

7 0
3 years ago
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