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fredd [130]
3 years ago
13

1. Mitchell got a job at Owens that pays $38,173 a year thanks to the help of an employment agency. The

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

38174:54*3*0.40

Step-by-step explanation:

1. calculate how much per week by

38174:54

2. than in 3 weeks

38174:54*3

3. than 40 percent of that

x*0.40

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How do I find the perimeter of a triangle with sides 3ft 8in., 2ft 10in., and 4 ft?
Dmitriy789 [7]
Formula for triangle perimeter is: a + b + c. In this scenario we have:

a = 3 feet 8 inches
b = 2 feet 10 inches
c = 4 feet

a + b + c =
= 3 ft + 8 in + 2 ft + 10 in + 4 ft =
= 9 ft + 18 in

We know that 1 foot is 12 inches, so we can simplify the result to this form:

10 ft + 6 in

or:

<u>10.5 feet</u>
4 0
3 years ago
Write an equation of the line that passes through the point (5, -8) with slope 5
Oxana [17]

\Large\texttt{Answer}

equation=\bold{y=5x-33}

\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}

\Large\texttt{Process}

<em>⇨ Use the formula below</em>

<em />\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}

<em>⇨ Substitute the parameters:</em>

<em />

<em />\bold{y-(-8)=5(x-5)}

\bold{y+8=5x-25}

\bold{y=5x-33}

Hope that helped

4 0
2 years ago
1. Martin can pour a concrete walkway in 6 hours working alone. Victor has
Bond [772]

Answer:

2.4 hr. = time working together

Step-by-step explanation:

Let x = time working together

x/6 = work done by Martin

x/4 = work done by Victor

Martin's part + Victor's part = 1 jog done

x/6 + x/4 = 1  Multiply thru by 12

2x + 3x = 12

5x = 12

x = 2.4 hr.

6 0
2 years ago
Determine LaShawn's average speed in meters per hour
abruzzese [7]
His average speed per minute is 1,448 meters per minute, and there are 60 minutes in a single hour. You would multiply 1,448 by 60 to get the answer of 86,880 meters per hour.
6 0
2 years ago
Which of the following is rational 9/12 or -64
natali 33 [55]
9/12 bc it is a fraction
3 0
2 years ago
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