What are the roots of the equation? 2x^2+x=6
2 answers:
Answer:
x = - 2, x =
Step-by-step explanation:
Given
2x² + x = 6 ( subtract 6 from both sides )
2x² + x - 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 6 = - 12 and sum = + 1
The factors are + 4 and - 3
Use these factors to split the x- term
2x² + 4x - 3x - 6 = 0 ( factor the first/second and third/fourth terms )
2x(x + 2) - 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(2x - 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
2x - 3 = 0 ⇒ 2x = 3 ⇒ x =
You might be interested in
Step-by-step explanation:
The area of a rectangle is 171 m²
Let l is the length and b is the width of the rectangle
It width is 10 m less than the length. So,
b = l-10 ...(1)
Area of a rectangle is given by :
or
l = 9 m or l = 19 m
If l = 9 m,
b = 9-10 = -1 m (can't be possible)
If l = 19 m
b = 19-10 = 9 m
So, the length an the breadth of the rectangle is 19 m and 9 m respectively.