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3 years ago

What is 7.2 times 10^5 equal to.

2 answers:

8 0

It is 72,000 all you have to do is subtract the number of places behind the decimal point from the exponent and then just add as many zeroes as the end product says

FromTheMoon [43]3 years ago

4 0

The answer to this is 720000

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I’m about to cry from frustration. Help please before I die

kvv77 [185]

Answer:

$\frac{1}{3}x+16=37$

63 Jelly Beans

Step-by-step explanation:

The unknown is the number of jelly beans originally in the bag or x

First he had x jelly beans

The he ate one-third of them

$\frac{1}{3}x$

He then ate 16 more jelly beans

$\frac{1}{3}x+16$

This was equal to 37 jelly beans

$\frac{1}{3}x+16=37$

This is the equation

Now solve for x

Subtract 16 from both sides

$\frac{1}{3}x=21$

Multiply both sides by 3

$x=63$

63 Jelly Beans

7 0

2 years ago

Read 2 more answers

Compare. >,< or = for each ? 7 yd 1 ft ? 25 ft , 38 in ? 3 ft

IceJOKER [234]

7 yd > 1 ft, 25 ft > 38 in. idk about that 3 ft there

3 0

3 years ago

Read 2 more answers

I need helpppp with 1-9

BigorU [14]

Hi!! What do you need help with? Solving the problems? Or understanding them? Also 1-9 is a bit blurry, so if you could retake it and repost it, I could solve for them. :). But if you don’t want to, don’t worry.

3 0

2 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago

Consider the right cones pictured below.

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

I just took it

8 0

3 years ago

Read 2 more answers