Could you please help me? -0.7-(-2.5)=

Mathematics

1 answer:

Reika [66]3 years ago

3 0

-0.7 - (-2.5) =

-0.7 + 2.5 =

2.5 - 0.7 = 1.8

1.8 is your answer

hope this helps

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Need help with son's homework I will give 30 points!!! Please show work

Elis [28]

Answer:

A. ⇒ The expression is b + 3

B. ⇒ The expression is 2b - 4

C. ⇒ The Dr's office is closer by 4 miles

Step-by-step explanation:

∵ The distance between Daniel's house and his school is b miles

∵ The swimming pool is 3 miles farther from his school

∴ The distance between Daniel's house and the swimming pool is b + 3

∵ The distance from Daniel's house to his Dr's office is 4 less than twice the distance from home to Daniel's school

∵ The distance between Daniel's house and his school is b

∴ The expression of distance from Daniel's house to his Dr's office is

2b - 4

∵ b = 3

∴ The distance between his house and swimming pool is:

3 + 3 = 6 miles

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∴ The Dr's office is closer to Daniel's house than the swimming pool by:

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Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premiu

AnnZ [28]

Premium rates are usually for premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202

<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
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Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

$\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun$