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3 years ago

Simplify (4x − 6) + (5x + 1). 9x + 5 9x − 5 x − 5 −x − 5

Mathematics

1 answer:

azamat3 years ago

3 0

Answer:

9x - 5

Step-by-step explanation:

<u>Simplify:</u>

(4x − 6) + (5x + 1) = ⇒ opening parenthesis
4x - 6 + 5x +1 =
(4x+ 5x) + (1 -6) = ⇒ grouping like terms
9x + (- 5) = ⇒ simplifying like terms
9x - 5 ⇒ answer

<u>Correct choice:</u> B. 9x -5

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W (n) = n^2-n find w (-3)

Papessa [141]

Answer:

$w(-3) = 12$

Step-by-step explanation:

Plug in -3 for n in the equation:

$w(n) = n^2 - n$

$w(-3) = (-3)^{2} - (-3)$

Simplify. Remember to follow PEMDAS. First, solve the power:

$w (-3) = (-3)^2 - (-3)\\w (-3) = (-3 * -3) - (-3)\\w (-3) = (9) - (-3)$

Next, combine like terms. Note that if there are two negative signs directly next to each other, it becomes a positive sign. Add:

$w(-3) = 9 - (-3)\\w(-3) = 9 + 3\\w(-3) = 12$

Your answer: $w(-3) = 12$

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3 years ago

Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of

jeka57 [31]

Answer:

c = 60.65 cm

Step-by-step explanation:

Given that,

The two sides of a triangle are 33 cm and 37 cm.

The angle between these two sides is 120°.

We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,

$c^2=a^2+b^2-2ab\cos C$

a = 33 cm, b = 37 cm and C is 120°

So,

$c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm$

So, the length of the third side of the triangle is 60.65 cm.

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3 years ago

The U.S.-based motorcycle manufacturer says that it expects to build 139,000 motorcycles this year, up from 126, 000 last year

german

The formula is (new-original)/original.

(139,000 - 126,000)/126,000

= 13,000/126,000

= .103

Now, convert the decimal into a percent by moving the decimal two places to the right and including the percent sign.

.103 = 10.3%

Answer: 10.3%

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garri49 [273]

Answer:

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3 years ago

Given that sin∅ = 1/4, 0 < ∅ < π/2, what is the exact value of cos∅?

Artemon [7]

Answer:

Step-by-step explanation:

Using the trigonometric identity

• sin²x + cos²x = 1 , hence

cosx = ± $\sqrt{1-sin^2x}$

cosΦ > 0 for 0 < Φ < $\frac{\pi }{2}$

cosΦ = $\sqrt{1-(\frac{1}{4})^2 }$ = $\sqrt{1-\frac{1}{16} }$ = $\sqrt{\frac{15}{16} }$ = $\frac{\sqrt{15} }{4}$ → b

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