Answer: the answer is 1469121
Step-by-step explanation:
The answer is: [C]: "no solution" .
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Given: 3y = 3/2 x + 6 ; Multiply each side by "2" ; to get rid of the fraction
2 * { 3y = 3/2 x + 6 } ; to get: 6y = 3x + 12
Given: 1/2 y –1/4 x = 3 ; Multiply EACH SIDE by "4" ; to get rid of the fraction ;
4 * { 1/2 y – 1/4 x = 3 } ; to get: 2y – x = 12 ;
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So we have:
6y = 3x + 12 ;
2y – x = 12 ;
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Multiply BOTH side of the "second equation" by "-1" ;
-1 * { 2y – x = 12 } ;
to get : x – 2y = -12 ;
Now, add "2y" to each side of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;
x – 2y + 2y = -12 + 2y ;
to get: x = 2y – 12 ;
Now, consider the "first equation" ;
6y = 3x + 12 ;
Divide EACH SIDE of this equation by "3" ;
6y / 3 = (3x + 12) / 3 ;
to get: 2y = x + 4 ;
Divide EACH SIDE of the equation by "2" ;
2y/ 2 = ( x + 4) /2 ;
to get: y = (x + 4) / 2 ;
Now plug in our calculated value for "x" ; which is:
" x = 2y – 12 " ; for the "x" values
y = [ (2y – 12)] + 4)] / 2 ;
y = (2y – 8 )/ 2
2y = 2y – 8 ??? ;;
The answer is: [C]: "no solution" .
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Answer:
1) r >-5 2) x >9
Step-by-step explanation:
Sec(x/2) = 1/cos(x/2)
sec(x/2)=cos(x/2) ----> cos^2(x/2)=1 ---> cos(x/2) = -1 and cos(x/2) = 1
Cos(x/2)=1 --- > x/2 = 0, only. x = 0;
cos(x/2)=-1 ----> x/2 = pi -> x = 2pi. But the statement says [0,2pi), so 2pi can not be chosen.
Only x = 0.
In fact, your equation is equivalent to sec(x)=cos(x), for x in [ 0, pi), so yes, only x = 0 .
There are fewer people on the bus.
The start of it had at least 5
The end of it had at least 1
