
is to say

for all

beyond some fixed

.
Similarly,

is to say

for all

.
From this we can gather that

where

is the larger of the two values

and

, or

. Then the last term is bounded above by

from which it follows that
Answer: x(2x²+5)
please give brainliest if it helped
Use the formula y2-y1/x2-x1.
3-3/-4-8
0/-12
The slope is 0, so the line is horizontal.
Any polynomial's graph cannot have two simultaneous maxima, so they must contain a minima between them. Thus, the total number of turning points of the graph is 3. Generally, when plotting a polynomial, the number of turning points is:
n = d -1; where d is the degree of the polynomial and n is the number of turning points. Thus, this function's degree must be at least 4. The answer is b.
Answer:
40
Step-by-step explanation:
The sum of measure of exterior angles is equal to 360
5x-20+2x+5+x+15+x = 360 add like terms
9x = 360 divide both sides by 9
x = 40