Question

+ 4x = 6(x - 2) - 4" alt="2(x - 8) + 4x = 6(x - 2) - 4" align="absmiddle" class="latex-formula">
how do I solve this one?​

Answer 1

In this question, you're solving for x.

Solve for x:

2(x - 8) + 4x = 6(x - 2) - 4

Distribute the 2 to the variables inside the parenthesis.

2x - 16 + 4x = 6(x - 2) - 4

Distribute the 6 to the variables inside the parenthesis.

2x - 16 + 4x = 6x - 12 - 4

6x - 16 = 6x - 12 - 4

6x - 16 = 6x - 16

Subtract 6x from both sides

-16 = -16

Add 16 to both sides

0 = 0

Answer:

All real numbers and solutions

Answer 2

2x-16+4x=6x-12-4
2x+4x=6x4-4
6x=6x
X=0