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bonufazy [111]
3 years ago
11

Need to confirm that I did work correctly.

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0
Y-int . . . x=0 . . . y-3 = 3 (0+1) . . . y-3 = 3 . . y=6. . . . . . . X-int .. y=0 .. 0-3=3 (x+1) .. -3=3x+3 ... -6=3x ...x=-2
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Let f(x) = x ^ 2 and g(x) = x - 3 . Evaluate (g?f)(0).
nignag [31]

Answer:

g(f(0))=-3

Step-by-step explanation:

we have

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substitute the variable x in the function g(x) by the function f(x)

so

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7 0
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schepotkina [342]

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3 0
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